1)we calculate the amount of the drug is left in the body 2 hours after the dose is administered.
t=2
A(t)=14(08)^t
A(t)=14(0.8)²=14(0.64)=8.96
Answer: after of two hours the amount of drug left in te body is 8.96 mg.
2)we calculate the time required to stay in the body 1 mg of drug.
A(t)=1
14(0.8)^t=1
ln [14(0.8)^t]=ln1
ln14+tln(0.8)=0
tln(0.8)=-ln 14
t=-ln 14 / ln (0.8)
t=11.8267...≈11.83
Answer: the time required is 11.83 hours (≈11 hours, 49 minutes, 48 seconds).
we are given
a function name g has input x=c
and range is all real numbers
Since, input is constant
but output is keep varying
so, this function would be vertical line in shape
and we can write that function as
.............Answer
Answer:

Step-by-step explanation:
Put the values of x (input) to the formulas of the functions

Answer:
D=6
Step-by-step explanation:
So, first, we can multiply 7x2=14. Then, it would be D+14=20. 20-14=6, so D=6.