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Tems11 [23]
3 years ago
7

Foil: (x+9)(3x-4)

Mathematics
1 answer:
QveST [7]3 years ago
3 0

QUESTION 1

The given binomial is;

(x+9)(3x-4)

First terms are multiplied: x\times 3x=3x^2

Outside terms are multiplied: x\times -4=-4x

Inside terms are multiplied: 9\times 3x=27x

Last terms are Multiplied: 9\times -4=-36

This gives us;

=3x^2-4x+27x-36

=3x^2+23x-36

QUESTION 2

We want to factor

6r^5s+4r^4s^2-8r^2s

The HCF is 2r^2s

We factor to get;

2r^2s(3r^3+2r^2s-4)

QUESTION 3;

x^2+x-2=0

Split the middle term;

x^2+2x-x-2=0

Factor

x(x+2)-1(x+2)=0

(x+2)(x-1)=0

(x+2)=0,(x-1)=0

x=-2,x=1

The solutions are;

x=-2 and x=1

These are the x-intercepts of the graph of the function

f(x)=x^2+x-2

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