The sum of geometric series will be:
(6^(1-1))+(6^(2-1))+(6^(3-1))+(6^(4-1))
=6^0+6^1+6^2+6^3
=1+6+36+216
=259
Answer: 259
Answer: -20/21
Step-by-step explanation:
Using the Pythagorean identity, we can get that the sine of angle theta is
.
But since theta terminates in Quadrant II, the sine of angle theta is positive, meaning that it has a value of 20/29.
Now, since tan = sin/cos, tan theta = (20/29)/(-21/29) = -20/21
The answer to your question is a,c,d
Answer:
The skydiver will fall 1600 ft in 10 seconds.
Step-by-step explanation:
<u>Distance a body falls from rest varies directly as the squares of the time it falls </u>
Let distance = s
time = t
Therefore , s = k ![\times t^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20t%5E%7B2%7D)
Given, the body falls 64 ft in 2 seconds.
Substituting in above equation,
64 = k ![\times (2)^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20%282%29%5E%7B2%7D)
64 = k ![\times (4)](https://tex.z-dn.net/?f=%20%5Ctimes%20%284%29%20)
k = ![\frac{64}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B64%7D%7B4%7D)
k = 16 ft/![s^{2}](https://tex.z-dn.net/?f=s%5E%7B2%7D)
We have to find how much he will fall in 10 seconds.
s = k ![\times t^{2}](https://tex.z-dn.net/?f=%20%5Ctimes%20t%5E%7B2%7D)
s = ![16 \times 10^{2}](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B2%7D)
s = ![16 \times 100](https://tex.z-dn.net/?f=16%20%5Ctimes%20100)
s = 1600 ft