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Yanka [14]
4 years ago
6

Solve cotx + 2cotxsinx = 0 for 0 degrees < or equal to x < or equal to 180 degrees

Mathematics
2 answers:
stealth61 [152]4 years ago
8 0

Step-by-step explanation:

cotx +2cotxsinx =0

cotx +2 \frac{cosx}{sinx}× sinx= 0

cotx +2 cosx= 0

\frac{cosx}{sinx}+ 2cosx= 0

\frac{cosx+ 2cosxsinx}{sinx} = 0

cosx +2 cosxsinx= 0

cosx ×(1+ 2sinx)= 0

Hence, either cosx= 0 that is x= 90° or 270°

or 1+ 2sinx = 0 that is sinx= \frac{-1}{2} i.e. x= 210° or 330°

As, 0° ≤x≤ 180° ∴ x= 90°

ikadub [295]4 years ago
7 0

Answer:

90°

Step-by-step explanation:

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