1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
AlekseyPX
3 years ago
13

Indicate which formula you would use to solve for the missing side B and then write your answer correct to two decimal places.Wr

ite only the formula down.. Single line text.

Mathematics
1 answer:
agasfer [191]3 years ago
4 0

Answer:

The measure of the angle b is approximately 44.040°.

Step-by-step explanation:

We need to apply Law of the Sine to determine the value of angle b, since the length of the side opposite to this side and another side length and its opposite angle are known. That is:

\frac{3.6}{\sin b} = \frac{5.1}{\sin 100^{\circ}}

\sin b = \frac{3.6}{5.1}\times \sin 100^{\circ}

b = \sin^{-1}\left(\frac{3.6}{5.1}\times \sin 100^{\circ} \right)

b \approx 44.040^{\circ}

The measure of the angle b is approximately 44.040°.

You might be interested in
In the example,-38+(-24)will be negative before finding the sum? ​
erastova [34]

Answer:

-62

Step-by-step explanation:

7 0
2 years ago
'Polonium-210 is a radioactive substance with a half-life of 138 days. If a nuclear
Tatiana [17]

Answer:

  • <u>59.0891 g (rounded to 4 decimal places)</u>

Explanation:

<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.

Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:

  • A=A_0\cdot (1/2)^n

Where:

  • A is the amount that remains of the substance after n half-lives have elapses, and
  • A₀ is the starting amount of the substance.

In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:

  • 330 days / 138 days = 2.3913

Therefore, the amount of polonium-210 that will be left in 330 days is:

  • A=310{g}\cdot (1/2)^{2.3913}=59.0891g
5 0
2 years ago
Given that f(x) = 2x + 5 and g(x) = x − 7, solve for f(g(x)) when x = −3.
WITCHER [35]
G(-3) = -3-7 = -10;
f(g(-3))=f(-10) = 2 x (-10) + 5 = - 20 + 5 = -15.
6 0
3 years ago
HELP - Wesley subscribes to a telecommunication company's move package. The plan includes a basic monthly charge of $40 and an a
boyakko [2]

Answer:

(month x 40) + (movies x C) or 40 + (M x C)     :/

Step-by-step explanation:

8 0
3 years ago
Pls brainlest ASAP and add extra points for correct answer
vlabodo [156]

Answer:

glucose, sunlight and oxygen on the left (they go in the cell)

water and carbon dioxide on the right (they go out of the cell)

3 0
3 years ago
Other questions:
  • A company makes cars at two factories. Some of the cars need repairs in the first year and some do not. This two-way frequency t
    8·1 answer
  • Ann Nguyen would like an installment loan for 5,000. Her bank will loan her the money at 12% for 18 months. Her insurance compan
    8·2 answers
  • 7x + 2y + 5 - 5x + Oy - 1<br> Simplify expresson
    8·1 answer
  • He system of equations can be solved using linear combination to eliminate one of the variables.
    12·2 answers
  • In the graph below, figure I undergoes a sequence of rotations, reflections, translations, and dilations to transform to figure
    6·1 answer
  • Can somebody plz help answer these questions correctly (only if u done this before) thx sm!
    14·1 answer
  • 5/9 times 3/7 WHOEVER ANSWERS IN UNDER 2 MINUTS I WILL MARK BRAINLIEST
    13·2 answers
  • Please, help me in this!! It's very difficult for me. I'm doing assignments in edgeunuity. Please help me in my assignment!!!
    8·1 answer
  • Fing the LCM of 54 and 81
    9·2 answers
  • The diameter of a cylindrical construction pipe is 3 ft. If the pipe is 14 ft long, what is its volume?Use the value 3.14 for n,
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!