Answer:
-62
Step-by-step explanation:
Answer:
- <u>59.0891 g (rounded to 4 decimal places)</u>
Explanation:
<em>Half-life time</em> of a radioactive substance is the time for half of the substance to decay.
Thus, the amount of the radioactive substance that remains after a number n of half-lives is given by:
Where:
- A is the amount that remains of the substance after n half-lives have elapses, and
- A₀ is the starting amount of the substance.
In this problem, you have that the half-live for your sample (polonium-210) is 138 days and the number of days elapsed is 330 days. Thus, the number of half-lives elapsed is:
- 330 days / 138 days = 2.3913
Therefore, the amount of polonium-210 that will be left in 330 days is:
G(-3) = -3-7 = -10;
f(g(-3))=f(-10) = 2 x (-10) + 5 = - 20 + 5 = -15.
Answer:
(month x 40) + (movies x C) or 40 + (M x C) :/
Step-by-step explanation:
Answer:
glucose, sunlight and oxygen on the left (they go in the cell)
water and carbon dioxide on the right (they go out of the cell)