The answer is 5 7/8
b/c 2 1/2 = 2 4/8
so then convert 8 3/8 as an improper fraction which is 67/8
and do the same w/ 2 4/8 which is 20/8
the do: 67/8 - 20/8 = 47/8
simplify 47/8 = 5 7/8.
Your answer is 5 7/8 inches of ribbon left.
The square pyramid looks exactly how it sounds. The base of the shape is a square and has 4 isosceles triangles that meet at a point. The square prism is like a 3D rectangle. It has 4 rectangles and 2 squares to close the shape.
Hope this helped.
:) Well, I dunno about anyone else but this question makes my head spin!
For this case we must simplify the following expression:
![\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}}](https://tex.z-dn.net/?f=%5Cfrac%20%7B6-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%7D%20%7B%5Csqrt%20%5B3%5D%20%7B9%7D%7D)
Multiplying the numerator and denominator by![(\sqrt [3] {9}) ^ 2](https://tex.z-dn.net/?f=%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%202)
![\frac {6-3 \sqrt [3] {6}} {\sqrt [3] {9}} * \frac {(\sqrt [3] {9}) ^ 2} {(\sqrt [3] { 9}) ^ 2} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B6-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%7D%20%7B%5Csqrt%20%5B3%5D%20%7B9%7D%7D%20%2A%20%5Cfrac%20%7B%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%202%7D%20%7B%28%5Csqrt%20%5B3%5D%20%7B%209%7D%29%20%5E%202%7D%20%3D)
We rewrite:
![\frac {\frac {6-3 \sqrt [3] {6}} * (\sqrt [3] {9}) ^ 2} {\sqrt [3] {9} * (\sqrt [3] {9 }) ^ 2} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B%5Cfrac%20%7B6-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%7D%20%2A%20%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%202%7D%20%7B%5Csqrt%20%5B3%5D%20%7B9%7D%20%2A%20%28%5Csqrt%20%5B3%5D%20%7B9%20%7D%29%20%5E%202%7D%20%3D)
By properties of powers we have that:
![a ^ m * a ^ n = a ^ {m + n}\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {(\sqrt [3] {9}) ^ 3} =\\\frac {(6-3 \sqrt [3] {6}) * (\sqrt [3] {9}) ^ 2} {9} =](https://tex.z-dn.net/?f=a%20%5E%20m%20%2A%20a%20%5E%20n%20%3D%20a%20%5E%20%7Bm%20%2B%20n%7D%5C%5C%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%20%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%202%7D%20%7B%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%203%7D%20%3D%5C%5C%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%20%28%5Csqrt%20%5B3%5D%20%7B9%7D%29%20%5E%202%7D%20%7B9%7D%20%3D)
We rewrite, moving the exponent within the radical:
![\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {9 ^ 2}} {9} =\\\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {81}} {9} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%20%5Csqrt%20%5B3%5D%20%7B9%20%5E%202%7D%7D%20%7B9%7D%20%3D%5C%5C%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%20%5Csqrt%20%5B3%5D%20%7B81%7D%7D%20%7B9%7D%20%3D)
We can rewrite
![\frac {(6-3 \sqrt [3] {6}) * \sqrt [3] {3 * 3 ^ 3}} {9} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%20%5Csqrt%20%5B3%5D%20%7B3%20%2A%203%20%5E%203%7D%7D%20%7B9%7D%20%3D)
We simplify:
![\frac {(6-3 \sqrt [3] {6}) * 3 \sqrt [3] {3}} {9} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B%286-3%20%5Csqrt%20%5B3%5D%20%7B6%7D%29%20%2A%203%20%5Csqrt%20%5B3%5D%20%7B3%7D%7D%20%7B9%7D%20%3D)
We apply distributive property:
![\frac {18 \sqrt [3] {3} -9 \sqrt [3] {18}} {9} =](https://tex.z-dn.net/?f=%5Cfrac%20%7B18%20%5Csqrt%20%5B3%5D%20%7B3%7D%20-9%20%5Csqrt%20%5B3%5D%20%7B18%7D%7D%20%7B9%7D%20%3D)
Simplifying we finally have:
![2 \sqrt [3] {3} - \sqrt [3] {18}](https://tex.z-dn.net/?f=2%20%5Csqrt%20%5B3%5D%20%7B3%7D%20-%20%5Csqrt%20%5B3%5D%20%7B18%7D)
Answer:
![2 \sqrt [3] {3} - \sqrt [3] {18}](https://tex.z-dn.net/?f=2%20%5Csqrt%20%5B3%5D%20%7B3%7D%20-%20%5Csqrt%20%5B3%5D%20%7B18%7D)
To find the volume, you need to do length times width times heightSO you have to do 5 times 5 times 6The volume is 150 cubic feetSince 150 cubic feet of this rectangular prism is 15 tonsyou can do 15 divided by 150so one cubic feet of this stone sculpture weight 0.1 tons