AD is perpendicular to BC so slope Ad = -1/slope of BC
Slope of BC = (2 - (-1)) / (- 6- 3) = 3 / -9 = -1/3
So slope of AD = -1 / (-1/3) = -3/-1 = 3 Answer
3m-10=2(4m-5)
3m-10=8m-10
3m-8m=-10+10
-5m=0
m=0
Answer:
0.318
Step-by-step explanation:
In the given triangle, the verteces are A(-4, 1), B(-6, 5), C(-1, 2).
A refrection across the x-axis will result in A'(-4, -1), B'(-6, -5), C'(-1, -2)
A translation of 1 unit to the right will result in A"(-3, -1), B"(-5, -5), C"(0, -2)
A translation of 1 unit down will result in A"'(-3, -2), B"'(-5, -6), C"'(0, -3) which corresponds to points DEF.
Therefore, the series of transformation required to transform ABC to DEF are <span>a reflection across the x-axis followed by a translation of 1 unit right and 1 unit down.</span>
