I think it’s D because the only thing that happen was that they rotated so I think it’s D but if it’s wrong sorry
A good place to start is to set to y. That would mean we are looking for to be an integer. Clearly, , because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since is a radical, it only outputs values from , which means y is on the closed interval: .
With that, we don't really have to consider y anymore, since we know the interval that is on.
Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval , which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:
Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.
Answer: the numbers were negative so he needed to add the positive numbers to that equation (I think sorry if I’m wrong)
Step-by-step explanation:
Answer:
It’s 4
Step-by-step explanation: