Since the distance is 560 miles and the bus goes 268 miles per hour, the answer can be given as:
If 268=1 hour
560=?
560/268*1 hour =2(rounded to nearest ones)
Therefore it will take the train approximately 2 hours to travel between both cities.

3 0

4 years ago

Use either Gaussian elimination or Gauss-Jordan elimination to solve the given system or show that no solution exists. (If there

True [87]

Answer:

x1 = t, x2 = -t and x3 = 0

Step-by-step explanation:

Given the system of equation

x1 + x2 + x3 = 0 .... 1

x1 + x2 + 9x3 = 0 .... 2

Subtract both equation

x3 - 9x3 = 0

-8x3 = 0

x3 = 0

Substitute x3 = 0 into equation 1

x1 + x2 + 0 = 0

x1+x2 = 0

x1 = -x2

Let t = x1

t = -x2

x2 = -t

Hence x1 = t, x2 = -t and x3 = 0

5 0

3 years ago

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

umka21 [38]

Since we know that the graph of our quadratic function has x-intercepts at (6,0) and (18,0), $x=6$ and $x=18$ are the zeroes of our quadratic. To find our quadratic we are going to factor each zero backwards and multiply them:
$x=6$
$x-6=0$
$x=18$
$x-18=0$

$(x-6)(x-18)=x^{2}-6x-18x+108$
$=x^{2}-24x+108$

Now that we have our quadratic function, we are going to use the average formula: $m= \frac{f(9)-f(3)}{9-3}$
$where$
$f(9)$ is the function evaluated at the 9th month
 $f(3)$ is the function evaluated at the 3rd month

$m= \frac{f(9)-f(3)}{9-3}$
$m= \frac{[9^{2}-24(9)+108]-[3^{2}-24(3)+108]}{9-3}$
$m= \frac{-27-45}{6}$
$m= \frac{-72}{6}$
$m=-12$

We can conclude that the closest approximate average rate of change for Edna's profits from the 3rd month to the 9th month is: B. −11.63 dollars per month.

6 0

3 years ago

Read 2 more answers