You could use the keep change flip method. You keep the 5/8, change the division sign to a multiplication sign, and flip the 16. 16 can also be written as 16/1, because it is the equivalent to 16. You flip it to 1/16. Then do the math.
5/8 x 1/16=5/128.
Hope it helped! If not, tell me what went wrong.
A function will have an absolute maximum when the velocity, dy/dx, is equal to zero and the acceleration, d2y/dx2, is less than zero. It will have a y-intercept of 4 if f(x)=4 when x=0.
In this case only f(x)=-x^2+2x+4 is equal to 4 when x=0. So we know that this is the correct answer. However taking the two derivatives proves that the function has an absolute maximum..
df/dx=-2x+2 and d2f/dx2=-2
Since acceleration is a constant negative two, we know that when velocity is equal to zero, it will be at an absolute maximum for f(x) at that point.
-2x+2=0
2x=2
x=1
So velocity equals zero when x=1, thus the absolute maximum of the quadratic, the vertex in this context, is f(1).
f(1)=-1+2+4=5
So the absolute maximum is at the point (1,5)
He received 102.18 dollars
Answer:
f⁻¹(x) = ± √x-6
Step-by-step explanation:
f(x) = x² + 6
y = x² + 6
x = y² + 6 ... replace x and y
solve y: y² = x - 6
y (f⁻¹(x)) = ± √x-6