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3 years ago

X°and x+2 are complementary angles then find the angles

Mathematics

1 answer:

Elanso [62]3 years ago

4 0

Answer:

44° and 46°

Step-by-step explanation:

Complementary angles sum to 90° , thus

x + x + 2 = 90

2x + 2 = 90 ( subtract 2 from both sides )

2x = 88 ( divide both sides by 2 )

x = 44

Thus the 2 angles are 44° and 44 + 2 = 46°

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If c ī b, what is m<2?

natulia [17]

Answer:

<2 = 90

Step-by-step explanation:

If the lines are perpendicular, the angles are 90 degrees

3 0

3 years ago

A study of one thousand teens found that the number of hours they spend on social networking sites each week is normally distrib

Svetradugi [14.3K]

Given:

Sample Mean = 30
Sample size = 1000
Population Standard deviation or σ=2
Confidence interval = 95%

to compute for the confidence interval

Population Mean or μ= sample mean ± (z×SE)

where:

SE→ Standard Error

SE=σ√n= 30√1000=0.9486

Critical Value of z for 95% confidence interval =1.96

μ=30±(1.96×0.9486)
μ=30±1.8594

Upper Limit

μ = 30 + 1.8594 = 31.8594

Lower Limit

μ = 30 − 1.8594 = 28.1406

answer: 28.1406<u<31.8594

3 0

3 years ago

If Bill wants to find the average of his family's heights. If his brother is 60 inches tall, his

Romashka [77]

Answer: 56 inches

Step-by-step explanation:

a. 60+58+64+72=254 (Add the average of his family without including him)

a. 62x5=310 (The average times 5, cause there are 5 of them will get you the total number of inches)

b. 310-254=56 (Subtract the total number of the 5 of them with the 4 of them to find Bill's height)

you can check your answer by adding all their heights.

4 0

1 year ago

What's the value of given expression <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B22%20%5Ctimes%2022%7D%20" id="TexFormula

scZoUnD [109]

Answer:

Step-by-step explanation:

square root of a number multiple by the himself give you the value

so square root of 22 x 22 = 22

5 0

3 years ago

Read 2 more answers

Simplify this please

Ugo [173]

Answer:

$\frac{12q^{\frac{7}{3}}}{p^{3}}$

Step-by-step explanation:

Here are some rules you need to simplify this expression:

Distribute exponents: When you raise an exponent to another exponent, you multiply the exponents together. This includes exponents that are fractions. $(a^{x})^{n} = a^{xn}$

Negative exponent rule: When an exponent is negative, you can make it positive by making the base a fraction. When the number is apart of a bigger fraction, you can move it to the other side (top/bottom). $a^{-x} = \frac{1}{a^{x}}$ , and to help with this question: $\frac{a^{-x}b}{1} = \frac{b}{a^{x}}$ .

Multiplying exponents with same base: When exponential numbers have the same base, you can combine them by adding their exponents together. $(a^{x})(a^{y}) = a^{x+y}$

Dividing exponents with same base: When exponential numbers have the same base, you can combine them by subtracting the exponents. $\frac{a^{x}}{a^{y}} = a^{x-y}$

Fractional exponents as a radical: When a number has an exponent that is a fraction, the numerator can remain the exponent, and the denominator becomes the index (example, index here ∛ is 3). $a^{\frac{m}{n}} = \sqrt[n]{a^{m}} = (\sqrt[n]{a})^{m}$

$\frac{(8p^{-6} q^{3})^{2/3}}{(27p^{3}q)^{-1/3}}$ Distribute exponent

$=\frac{8^{(2/3)}p^{(-6*2/3)}q^{(3*2/3)}}{27^{(-1/3)}p^{(3*-1/3)}q^{(-1/3)}}$ Simplify each exponent by multiplying

$=\frac{8^{(2/3)}p^{(-4)}q^{(2)}}{27^{(-1/3)}p^{(-1)}q^{(-1/3)}}$ Negative exponent rule

$=\frac{8^{(2/3)}q^{(2)}27^{(1/3)}p^{(1)}q^{(1/3)}}{p^{(4)}}$ Combine the like terms in the numerator with the base "q"

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)}q^{(1/3)}}{p^{(4)}}$ Rearranged for you to see the like terms

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(2)+(1/3)}}{p^{(4)}}$ Multiplying exponents with same base

$=\frac{8^{(2/3)}27^{(1/3)}p^{(1)}q^{(7/3)}}{p^{(4)}}$ 2 + 1/3 = 7/3

$=\frac{\sqrt[3]{8^{2}}\sqrt[3]{27}p\sqrt[3]{q^{7}}}{p^{4}}$ Fractional exponents as radical form

$=\frac{(\sqrt[3]{64})(3)(p)(q^{\frac{7}{3}})}{p^{4}}$ Simplified cubes. Wrote brackets to lessen confusion. Notice the radical of a variable can't be simplified.