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anygoal [31]
3 years ago
5

Which two ratios form a proportion? A) 3 : 4 and 6 : 12 B) 3 : 4 and 9 : 15 C) 3 : 4 and 12 : 18 D) 3 : 4 and 15 : 20

Mathematics
2 answers:
weqwewe [10]3 years ago
4 0
The answer to this question is D
Andre45 [30]3 years ago
3 0

Answer:

d forms a proportion

Step-by-step explanation:

3x5=15,4×5=20

so they both increase protionally

therefore they are protional

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Which of the following tables represents a function?
quester [9]

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B seems right

Step-by-step explanation:

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3 years ago
What is the surface area of the rectangular prism below? 8 19 8​
user100 [1]
The answer is c because S=Ph+2b
5 0
3 years ago
Express this to single logarithm
zzz [600]

Answer:  \log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

  1. log(A) + log(B) = log(A*B)
  2. log(A) - log(B) = log(A/B)
  3. B*log(A) = log(A^B)

From there, we can then say the following:

\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}

8 0
2 years ago
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