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3 years ago

Find the complete factored form of the polynomial: 35ab4+14a6b3

Mathematics

1 answer:

guapka [62]3 years ago

5 0

35ab⁴ + 14a⁶b³

7ab³ (5b + 2a⁵)

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The bike shop charges $10 for flat tire repair and $40 for a full tuneup. The total receipts for services was $3000. 10 tuneup’s

jonny [76]

Answer:

260 flat tyres were repaired.

$400 of sales in full tuneups

$2600 of sales in flat tyre repairs

Step-by-step explanation:

$40 x 10 = $400

$3000 - $400 = $2600

$2600 ÷ $10 = 260 flat tyres

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3 years ago

A farmer in Gervais is raising zebras and elephant. Last week, she bought 15 bags of feed. Zebra feed costs $35 a bag and elepha

morpeh [17]

Answer:

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Step-by-step explanation:

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2 years ago

When you got your car fixed, the cost for parts was $75. The cost for labor was $45 per hour. If the total cost was $255 . Find

navik [9.2K]

Answer:

3.3

Step-by-step explanation:

Hour : H

subtract the 75 from both sidesso the variable would be on one side and the knowns would be on the other side

45H + 75 = 225

-75 -75

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45H = 150

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3.33

6 0

3 years ago

Jamie knows the lengths of 2 sides of a triangle are 8

myrzilka [38]

 $answer \\ 4 < s < 20 \\ solution \\ 12 - 8 < s < 12 + 8 \\ = 4 < s < 20 \\ hope \: it \: helps$ 

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3 years ago

Given that f.x 3x-2 over x+1 g[x] x +5 evaluate f[-4] and gf [-2]

Jobisdone [24]

The value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

<h3>What is the value of f[-4] and g°f[-2]?</h3>

Given the function;

$f(x) = \frac{3x-2}{x+1}$
$g(x)=x+5$
f[ -4 ] = ?
g°f[ -2 ] = ?

For f[ -4 ], we substitute -4 for every variable x in the function.

$f(x) = \frac{3x-2}{x+1}\\\\f(-4) = \frac{3(-4)-2}{(-4)+1}\\\\f(-4) = \frac{-12-2}{-4+1}\\\\f(-4) = \frac{-14}{-3}\\\\f(-4) = \frac{14}{3}$

For g°f[-2]

g°f[-2] is expressed as g(f(-2))

$g(\frac{3x-2}{x+1}) = (\frac{3x-2}{x+1}) + 5\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2}{x+1} + \frac{5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{3x-2+5(x+1)}{x+1}\\\\g(\frac{3x-2}{x+1}) = \frac{8x+3}{x+1}\\\\We\ substitute \ in \ [-2] \\\\g(\frac{3x-2}{x+1}) = \frac{8(-2)+3}{(-2)+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-16+3}{-2+1}\\\\g(\frac{3x-2}{x+1}) = \frac{-13}{-1}\\\\g(\frac{3x-2}{x+1}) = 13$

Therefore, the value of f[ -4 ] and g°f[-2] are $\frac{14}{3}$ and 13 respectively.

Learn more about composite functions here: brainly.com/question/20379727

#SPJ1

6 0

2 years ago