Answer and Explanation: In enzyme kinetics, one constant describing enzyme activity is <em>Maximal Velocity</em> (Vmax). It indicates how fast an enzyme can catalyze the reaction. It is dependent on substrate concentration.
As the muscle is an organ which needs a great amount of energy, the enzyme glycogen phosphorilase is very active on the organ, compared to the liver, where glicose is stored. So, the Vmax of glycogen phosphorylase expressed in muscle is faster than when expressed in the liver, means the enzyme in muscle has a bigger concentration of substrate and therefore will reach Vmax faster, i.e. will be significantly larger.
Options for part A are as follows:
A) A mutation in the operator sequence
B) A mutation in the lac-Z gene
C) A mutation in the lac-Y gene
D) A super repressor mutation
Answer:
The correct answer:
Part a - A mutation in the operator sequence
Part b - It ensures that a cell dedicates resources to the production of enzymes involved in lactose metabolism only when lactose is available in the environment
Part C. true.
Explanation:
part a:
If there is a mutation in the operator sequence leads to prevent binding of the repressor which leads to allowing constitutive expression of the genes various conditions.
part b:
The biological role of the lac operon makes sure that the cell dedicates resources to the production of enzymes involved in lactose metabolism only when lactose is available in the environment
Part c:
RNA polymerase cannot transcribe the structural genes due to the repressor binds to the lac operator, therefore, the proper function of the lac operon is possible when the placement of the operator sequence between the promotor and the structural genes.
Answer:
Given merely 40 butterflies were marked, assumed that there were multiple captures of both marked and unmarked butterflies, that the butterflies caught in traps were on the loose to be caught again. There are two mathematical solutions for this, both yielding the same answer which is 100.
• First, to each marked butterfly was taken twice (40 marked X2 = 80 captured) then of the unmarked butterflies the 120 captured must relate to 60 actual butterflies. In which 40 + 60 = 100.
• Secondly, by means of ratios in which 80/200 = 40/X. In this case X also = 100 that will result to the estimated size of the population of wilson park is 100.
Explanation:
Sebaceous glands shrink in size :) hope that's you out
