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charle [14.2K]
4 years ago
14

SqrR(3x^12 * y^10) / SqrR(5x^6 * y^3)

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
8 0
What we are going to do in this case is to simplify the expression step by step.
 We have then:
 SqrR (3x ^ 12 * y ^ 10) / SqrR (5x ^ 6 * y ^ 3)
 SqrR (3x ^ 12 * y ^ 10 * y) / SqrR (5x ^ 6 * y ^ 3 * y)
 We use square root properties:
 ((x ^ 6 * y ^ 5) * SqrR (3y)) / ((x ^ 3 * y ^ 2) * SqrR (5))
 We use power properties:
 ((x ^ (6-3) * y ^ (5-2)) * SqrR (3y)) / (SqrR (5))
 ((x ^ 3 * y ^ 3) * SqrR (3y)) / (SqrR (5))
 ((x ^ 3 * y ^ 3) * SqrR (15y)) / (SqrR (25))
 1/5 * ((x ^ 3 * y ^ 3) * SqrR (15y))
 Answer:
 
D. none of these
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Given ADC ACB and BDC BCA prove a squared + b squared = c squared. Use the two Column proof.
Yuri [45]

Answer:

a²  + b²  = c · (e + d) =  c × c = c²

a²  + b²  = c²

Please see attachment

Step-by-step explanation:

Statement,                                                        Reason

ΔADC ~ ΔACB,          Given

AC/AD = BA/AC,        The ratio of corresponding sides of similar triangles

b/e = c/b

b² = c·e

ΔBDC ~ ΔBCA,           Given

BC/BA =  BD/BC,        The ratio of corresponding sides of similar triangles

a/c = d/a        

a² = c·d

a²  + b²   = c·e + c·d

a²  + b²   = c · (e + d)

e + d = c,                       Addition of segment

a²  + b²   = c × c = c²

Therefore, a²  + b²   = c²

7 0
3 years ago
Determine the ratio in which the point (–6, m) divides the join of A(–3, –1) and B(–8, 9). Also, find the value of m.
PSYCHO15rus [73]

Answer:

Ratio = 3 : 2 and value of m = 5.

Step-by-step explanation:

We are given the end points ( -3,-1 ) and ( -8,9 ) of a line and a point P = ( -6,m ) divides this line in a particular ratio.

Let us assume that it cuts the line in k : 1 ratio.

Then, the co-ordinates of P = ( \frac{-8k-3}{k+1},\frac{9k-1}{k+1} ).

But, \frac{-8k-3}{k+1} = -6

i.e. -8k-3 = -6k-6

i.e. -2k = -3

i.e. k = \frac{3}{2}

So, the ratio is k : 1 i.e \frac{3}{2} : 1 i.e. 3 : 2.

Hence, the ratio in which P divides the line is 3 : 2.

Also, \frac{9k-1}{k+1} = m where k = \frac{3}{2}

i.e. m = \frac{\frac{9 \times 3}{2}-1}{\frac{3}{2}-1}

i.e. m = \frac{27-2}{3+2}

i.e. m = \frac{25}{5}

i.e. m = 5.

Hence, the value of m is 5.

4 0
3 years ago
Read 2 more answers
Help? which one is it
Dennis_Churaev [7]
5 is the correct answer
5 0
3 years ago
Find the values of C for which C(x+2)—(x+2)(x–2)=0 has just one solution. please help me ASAP ​
CaHeK987 [17]
<h3>Answer:   C = -4</h3>

==================================================

Work Shown:

C(x+2) - (x+2)(x-2) = 0

(x+2)(C-(x-2)) = 0

(x+2)(C-x+2) = 0

x+2 = 0 or C-x+2 = 0

x = -2 or x = C+2

If we want one solution only, then we must make C+2 = -2 which solves to C = -4

If C = -4, then x = C+2 = -4+2 = -2 which matches with the first solution mentioned. If C is anything else but -4, then we'd have two different solutions (eg: C = 10 leads to x = C+2 = 12 as the other solution)

3 0
2 years ago
Help me with this please please pleasee
Mazyrski [523]

Answer:

37.79924

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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