3 years ago

Help me with this please please pleasee

Mathematics

2 answers:

Mazyrski [523]3 years ago

5 0

Answer:

37.79924

Step-by-step explanation:

Veronika [31]3 years ago

5 0

37.79924 that will be your answerw

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Consider the equation below. (if an answer does not exist, enter dne.) f(x) = x4 − 32x2 + 5 (a) find the interval on which f is

ivann1987 [24]

The function f(x) is increasing on the interval (-4, 0) ∪ (4, ∞).

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3 years ago

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in one week a kiln removes 1/3 of the moisture from a stack of wood. What fraction of the moisture remains in the lumber after 5

Evgesh-ka [11]

Answer:

-1 2/3 that's the best i could do sorry if its wrong

Step-by-step explanation:

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3 years ago

Solve the equation 6(z + 8.5) = 123

kakasveta [241]

I believe it’s z = 12

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3 years ago

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Use the following image to assist in your answer.<br> a =<br> - 6<br> - 9<br> - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

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3 years ago

If 1/p+q=r and p≠-q, what is p in terms of r and q?

bekas [8.4K]

p = (1/r) - q

In order to find this, follow the order of operations to get the answer.

1/p+q = r ----> Multiply both sides by p+q

1 = r(p + q) -----> Divide by r

1/r = p + q -----> subtract q from both sides

(1/r) - q = p

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3 years ago