Answer:
a) Var[z] = 1600
D[z] = 40
b) Var[z] = 2304
D[z] = 48
c) Var[z] = 80
D[z] = 8.94
d) Var[z] = 80
D[z] = 8.94
e) Var[z] = 320
D[z] = 17.88
Step-by-step explanation:
In general
V([x+y] = V[x] + V[y] +2Cov[xy]
how in this problem Cov[XY] = 0, then
V[x+y] = V[x] + V[y]
Also we must use this properti of the variance
V[ax+b] = 
V[x]
and remember that
standard desviation = ![\sqrt{Var[x]}](https://tex.z-dn.net/?f=%5Csqrt%7BVar%5Bx%5D%7D)
a) z = 35-10x
Var[z] = 
Var[x] = 100*16 = 1600
D[z] = 
= 40
b) z = 12x -5
Var[z] = 
Var[x] = 144*16 = 2304
D[z] = 
= 48
c) z = x + y
Var[z] = Var[x+y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = 
= 8.94
d) z = x - y
Var[z] = Var[x-y] = Var[x] + Var[y] = 16 + 64 = 80
D[z] = = 8.94
e) z = -2x + 2y
Var[z] = 4Var[x] + 4Var[y] = 4*16 + 4*64 = 320
D[z] = 
= 17.88
Answer:
Neither.
Step-by-step explanation:
I am not completely sure, so make sure to also let other answer this before you trust me lol. I really hope this helps!!
Answer:
37.3032cm^2
Step-by-step explanation:
Given data
Diameter= 0.6cm
Radius= 0.3cm
Lenght = 19.5cm
Surface area (A) =2πrh+2πr^2
Substitute
A=2*3.14*0.3*19.5+2*3.14*0.3^2
A=36.738+0.5652
A=37.3032
Hence the surface area is
37.3032cm^2
Answer: 
Step-by-step explanation:
1. You have the following function given in the problem:
2. Then, to find 
asked in the exercise, you only need to substitute 
(which is the input value) into the given function.
3. Therefore, keeping the above on mind, you obtain that is:
