(x-1)(x-1)
=x^2-x-x+1
=x^2-2x+1
(x+7)(x-7)
=x^2-7x+7x-49
=x^2-49
Answer:
0.6 = 60% probability that he or she studies on a weeknight.
Step-by-step explanation:
We solve this question treating these events as Venn probabilities.
I am going to say that:
Probability A: Probability of a student studying on weeknights.
Probability B: Probability of a student studying on weekends.
Forty-two percent of students said they study on weeknights and weekends
This means that 
47% said they studied on weekends
This means that 
65% said they study either on weeknights or weekends.
This is 
If you were to pick one student at random, what is the probability that he or she studies on a weeknight?
This is P(A), and the equation used is:

Considering the values we have:



0.6 = 60% probability that he or she studies on a weeknight.
He would be going at a rate of
51 meters per second
Could you mark the Brainliest?
<h3>
Answer: $611</h3>
Work Shown:
30% of 470 = 0.30*470 = 141
The value goes up by $141, so the answer would be 470+141 = $611
A slight shortcut would be to say
1.30*470 = 611
This works because 1.30 = 1 + 0.30 = 100% + 30%
Answer: The distance is 30
Step-by-step explanation:
To find the distance between the two points,find the difference between the x and y values, square them and add them to find their square root.
10 - (-14) = 24
-16 - 2= -18
24^2 + 18^2 = d^2 where d is the distance
576 + 324 = d^2
900 =d^2
d =
d= 30