Answer:
10d or less
Step-by-step explanation:
Joanne would want $50 left, and she has $250. 20 - 50 is 200. 20 goes into 100 5 times.
20 goes into 200 10 times. You just add five. (20, 40, 60, 80, 100)
If she wants at least $50 left, she would have to limit how many Dvd's she buys to 10 or less.
Answer:
c) 0.0156
Step-by-step explanation:
The general term a[n] of a geometric sequence is given in terms of the first term a[1] and common ratio r as ...
a[n] = a[1]r^(n-1)
The given sequence has an initial term of a[1]=8 and a common ratio of 4/8=1/2. Then the general term is ...
a[n] = 8(1/2)^(n-1)
The 10th term is then ...
a[10] = 8(1/2)^(10-1) = 8(1/2)^9 = 8/512
a[10] = 0.015625 ≈ 0.0156
Answer: Choice D
b greater-than 3 and StartFraction 2 over 15 EndFraction
In other words,
b > 3 & 2/15
or
========================================================
Explanation:
Let's convert the mixed number 2 & 3/5 into an improper fraction.
We'll use the rule
a & b/c = (a*c + b)/c
In this case, a = 2, b = 3, c = 5
So,
a & b/c = (a*c + b)/c
2 & 3/5 = (2*5 + 3)/5
2 & 3/5 = (10 + 3)/5
2 & 3/5 = 13/5
The inequality 
is the same as 
---------------------
Let's multiply both sides by 15 to clear out the fractions
---------------------
Now isolate the variable b
Side note: Another way to go from 47/15 to 3 & 2/15 is to notice how
47/15 = 3 remainder 2
The 3 is the whole part while 2 helps form the fractional part. The denominator stays at 15 the whole time.
The van is traveling about 55.9 miles per hour.
The solutions will lie in all the four quadrants.
y≤2/7x+1
We have the following inequality:
y=2/7x+1
If x=0
y=2/7(0) +1
y=1
If y=0
x=-3.5
So the line passes through the points:
(0,1) and (-3.5,0)
To find the shaded region, let us take a point, namely, the origin and test it in the inequality:
y≤ 2/7x +1
0≤ 2/7(0) +1
0≤ 1 which is true
Since this is true, then the shaded region includes this point. This is shown below and as you can see the solutions exist in all four quadrants.
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