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Shkiper50 [21]
3 years ago
9

A copy of the copyrighted work must be exactly the same as the original to infringe a copyright.

Computers and Technology
1 answer:
nordsb [41]3 years ago
7 0

Answer:

true

Explanation:

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The largest country in South America
ioda

Answer:

it's argentinian

Explanation:

7 0
3 years ago
In how many ways can the letters of the word APPROXIMATION be arranged?
ZanzabumX [31]

Answer:

2494800

Explanation:

A lot of math and time.

5 0
3 years ago
PLEASE HELP what is the mechanical advantage of a wheel with a radius of 8.0 cm connected with a axle with a radius of 2.5 cm?
Paraphin [41]
3.2 i believe. I looked it up though
5 0
3 years ago
Read 2 more answers
A computer hard disk starts from rest, then speeds up with an angular acceleration of 190 rad/s2 until it reaches its final angu
Nataly_w [17]
The first thing we are going to do is find the equation of motion:
 ωf = ωi + αt
 θ = ωi*t + 1/2αt^2
 Where:
 ωf = final angular velocity
 ωi = initial angular velocity
 α = Angular acceleration
 θ = Revolutions.
 t = time.
 We have then:
 ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
 ωi = 0
 α = 190 rad / s2
 Clearing t:
 753.60 = 0 + 190*t
 t = 753.60 / 190
 t = 3.97 s
 Then, replacing the time:
 θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
 θ1 = 1494.51 rad
 For (10-3.97) s:
 θ2 = ωf * t
 θ2 = (753.60 rad / s) * (10-3.97) s
 θ2 = 4544,208 rad
 Number of final revolutions:
 θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
 θ1 + θ2 = 961.57 rev
 Answer:
 the disk has made 961.57 rev 10.0 s after it starts up
3 0
3 years ago
Read 2 more answers
Using Matlab programming I need to rotate the line defined by x,y by 45 degrees around 2,2
belka [17]

Answer:

% here x and y is given which we can take as

x = 2:2:10;

y = 2:2:10;

% creating a matrix of the points

point_matrix = [x;y];

%  center point of rotation  which is 2,2 here

x_center_pt = x(2);

y_center_pt = y(2);

% creating a matrix of the center point

center_matrix = repmat([x_center_pt; y_center_pt], 1, length(x));

% rotation matrix with rotation degree which is 45 degree

rot_degree = pi/4;      

Rotate_matrix = [cos(rot_degree) -sin(rot_degree); sin(rot_degree) cos(rot_degree)];

% shifting points  for the center of rotation to be at the origin

new_matrix = point_matrix - center_matrix;  

% appling rotation  

new_matrix1 = Rotate_matrix*new_matrix;          

Explanation:

We start the program by taking vector of the point given to us and create a matrix by adding a scaler to each units with repmat at te center point which is (2,2). Then we find the rotation matrix by taking the roatational degree which is 45 given to us. After that we shift the points to the origin and then apply rotation ans store it in a new matrix called new_matrix1.

4 0
3 years ago
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