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amm1812
3 years ago
14

How is the graph of y=x^2 different from the graph of y=x^2-2

Mathematics
1 answer:
Zinaida [17]3 years ago
5 0
It is two units shifted downwards. you can see it by substituting x=0 for both equations
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Bad White [126]
Answer:

A) 8 days!!!!!
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3 years ago
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X-6y-7=0. What is equation in general form.
son4ous [18]

Answer:

y=1/6x-7/6

Step-by-step explanation:

-6y = -x + 7

y = x/6 - 7/6

This is assuming you mean in standard form.

Also, you may have to write it as 'y=1/6x-7/6'

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4 years ago
Erica plotted the three towns closest to her house on a graph with town AA at (9, 12), town BB at (9, 7) and town CC at (1, 1).
Sliva [168]
To compute the distance between the points, we can apply the distance formula as shown below.

d = \sqrt{(x_{1} - x_{2})^{2} + (y_{1} - y_{2})^{2} }

In which x₁ and x₂ are the x-coordinates and y₁ and y₂ are the y-coordinates of the two points. Thus, applying this with the segments AABB, AACC, and BBCC, we have

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\overline{BBCC} = \sqrt{(9-1)^{2} + (7-1)^{2}} = 10

Now that we have the lengths of all the sides of ΔAABBCC, we can find the missing angles using the Law of Cosines.

Generally, we have

c^{2} = a^{2} + b^{2} - 2abcosC

or

C = cos^{-1} (\frac{a^{2} + b^{2} - c^{2}}{2ab})

Hence, we have

\angle AA = cos^{-1} (\frac{(\sqrt{185})^{2} + 5^{2} - 10^{2}}{2(5)(\sqrt185)})
\angle BB= cos^{-1} (\frac{5^{2} + 10^{2} - (\sqrt{185})^{2}}{2(5)(10)})
\angle CC= cos^{-1} (\frac{10^{2} + (\sqrt{185})^{2} - 5^{2}}{2(5)(\sqrt{185})})

Simplifying this, we have

\angle AA = 36.03^{0}
\angle BB = 126.87^{0}
\angle CC = 17.10^{0} 

Thus, from this, we can arrange the angles from smallest to largest: ∠CC, ∠AA, and ∠BB.

Answer: ∠CC, ∠AA, and ∠BB
3 0
3 years ago
Thank u in advance!!
Dafna1 [17]

Answer:

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Step-by-step explanation:

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Dilation does not preserve side length, so it is not a congruence transformation.

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Answer:4

Step-by-step explanation:

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