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Irina-Kira [14]
4 years ago
12

Use Lagrange multipliers to find the volume of the largest rectangular box in the first octant with three faces in the coordinat

e planes and one vertex in the planex + 9y + 4z = 27.
Mathematics
1 answer:
Anni [7]4 years ago
6 0

Answer:

81/4

Step-by-step explanation:

From the given information; we are to use Lagrange multipliers to find the volume of the largest rectangular box

The coordinate planes and the vertex given in the plane is x + 9y + 4z = 27.

By applying Lagrange multipliers, we have;

fx = \lambda gx

where;

f: V = xyz

g : x + 9y + 4z = 27

From; fx = \lambda gx

yz = \lambda    --------- equation (1)

From; fy = \lambda gy

xz = 9 \lambda  --------- equation (2)

From; fz = \lambda gz

xy = 4 \lambda --------- equation (3)

Comparing and solving equation (1),(2) and (3);

\lambda x = 9 \lambda y = 4 \lambda z

divide through by \lambda

x = 9 y = 4z

3x = 27

x = 27/3

x = 9

From x = 9y

9 = 9 y

y = 9/9

y = 1

From

x = 4z

9 = 4 z

z = 9/4

Thus; the Volume of the largest rectangular box = 9 × 1  × 9/4

= 81/4

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Elimination_4x_2y=14<br> _10x+7y=_24
Gnesinka [82]

Answer:

The answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

Step-by-step explanation:

Given:

-4x-2y=14

-10x+7y=-24

Now, to solve it by elimination:

-4x-2y=14   ......(1)

-10x+7y=-24 ......(2)

So, we multiply the equation (1) by 7 we get:

-28x-14y=98

And, we multiply the equation (2) by 2 we get:

-20x+14y=-48

Now, adding both the new equations:

-28x-14y+(-20x+14y)=98+(-48)

-28x-14y-20x+14y=98-48

-28x-20x-14y+14y=50

-8x=50

<em>Dividing both the sides by -8 we get:</em>

x=-\frac{50}{8}

Now, putting the value of x in equation (1):

-4x-2y=14

-4(-\frac{50}{8})-2y=14

\frac{200}{8} -2y=14

25-2y=14

<em>Subtracting both sides by 25 we get:</em>

-2y=-11

<em>Dividing both sides by -2 we get:</em>

y=\frac{11}{2}

Therefore, the answer is x=-\frac{50}{8}  and y=\frac{11}{2}.

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Step-by-step explanation:

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