Given the equation, y= 1/3 x - 4. what is the slope and the y-intercept?

Please help with hair question- it’s in the photo

Levart [38]

Salutations!

Growth meters per second = 4.8 × $10^{-9}$

First, you need to convert standard form into a normal number.

4.8 × $10^{-9}$ = 4.800000000

a) In one day there are 24 hours, therefore you will multiplying 4.800000000 and 24

4.800000000 × 24 = 115.2 = 115.2 × $10^{-9}$ (standard form)

b) 365 days in a year, so multiply 4.800000000 and 365

4.800000000 × 365 = 1752 = 1.7 × $10^{3}$ (standard form)

Hope I helped (:

have a great day!

3 0

3 years ago

Geneva treated her parents to dinner at their favorite restaurant the bill was $74.25 Geneva wants to leave 16% of the total tip

Tanya [424]

Answer: The tip would be $11.88.

Step-by-step explanation: Basically, to find the tip of the bill you need to multiply the total, $74.25 by the tip amount which is 16%. To do this you will first need to convert 16% to a decimal. To find the decimal, divide 16 by 100 to get 0.16. Next, you will need to multiply the total of the bill $74.25 by the decimal 0.16. 74.25 multiplied by 0.16 is 11.88. So, the tip would be $11.88.

6 0

3 years ago

State the domain and range of the following relation.<br> (picture included) <br> please help!

Akimi4 [234]

Domain = what x values are used
Range = what y values are used

so duplicates do not matter, ascending ordering is useful.

Then you can find that answer C correctly lists the right values.

5 0

4 years ago

A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken

mihalych1998 [28]

Answer:

n=6147

Step-by-step explanation:

1) Notation and definitions

$X=1$ number of citrus trees that are infected with the citrus red mite.

$n=5$ random sample taken

$\hat p=\frac{1}{5}=0.2$ estimated proportion of citrus trees that are infected with the citrus red mite.

$p$ true population proportion of citrus trees that are infected with the citrus red mite.

Me=0.01 represent the margin of error desired

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{\hat p(1-\hat p)}{n}})$

In order to find the critical values we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values would be given by: