First, we are given that the inscribed angle of arc CB which is angle D is equal to 65°. This is half of the measure of the arc which is equal to the measure of the central angle, ∠O.
m∠O = 2 (65°) = 130°
Also, the measure of the angles where the tangent lines and the radii meet are equal to 90°. The sum of the measures of the angle of a quadrilateral ACOB is equal to 360°.
m∠O + m∠C + m∠B + m∠A = 360°
Substituting the known values,
130° + 90° + 90° + m∠A = 360°
The value of m∠A is equal to 50°.
<em>Answer: 50°</em>
Honestly man i don’t know Im in 6th grade bro
Answer: At least 7
Step-by-step explanation:
A good tip is to cut the same shape and fold it and count how many symmetry :)
We have that
<span>(-3,7) is on the graph of f(x), find the corresponding point for the function
f(x + 5)
we know that
in the transformation f(x)-------> f(x+5)
the point (x.y) in f(x) becomes a point (x-5,y) in f(x+5)
so
(-3,7)-----------> becomes a point (-3-5,7)------> (-8,7)
the answer is
</span>(-8,7)<span>
</span>
