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Komok [63]
3 years ago
10

A shuttle leaving Earth's atmosphere travels 15 miles every 2 seconds. When entering the Earth's atmosphere, the shuttle travels

2 3/8 miles per 1/2 second. Find the difference in the distances traveled after 15 seconds when leaving and entering the atmosphere.
Mathematics
1 answer:
sveta [45]3 years ago
5 0

41 ¼ miles

Step-by-step explanation:

When leaving Earth's atmosphere;

15 miles / 2 sec

Therefore it travels 15/2 miles / sec

In 15 seconds the shuttle will have traveled;

15/2  miles * 15 sec

= 225/2

= 112 ½ miles  

When entering the Earth's atmosphere;

2 3/8 miles / ½ sec

Therefore, in one sec it travels 2 3/8 miles * 2

19/8 * 2

= 19/4 miles / sec

In 15 seconds the shuttle will have traveled;

19/4 miles  * 15 sec

= 285/4

= 71 ¼ miles

The difference in the distances traveled after 15 seconds when leaving and entering the atmosphere;

112 ½ miles   - 71 ¼ miles

= 41 ¼ miles

Learn More:

brainly.com/question/12397541

brainly.com/question/8311838

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