Answer:
x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3
Step-by-step explanation:
Solve for x over the real numbers:
(9 x - 4)^2 = 18
Take the square root of both sides:
9 x - 4 = 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)
Add 4 to both sides:
9 x = 4 + 3 sqrt(2) or 9 x - 4 = -3 sqrt(2)
Divide both sides by 9:
x = 4/9 + sqrt(2)/3 or 9 x - 4 = -3 sqrt(2)
Add 4 to both sides:
x = 4/9 + sqrt(2)/3 or 9 x = 4 - 3 sqrt(2)
Divide both sides by 9:
Answer: x = 4/9 + sqrt(2)/3 or x = 4/9 - sqrt(2)/3
Go learn how to do these with calculator s and find the sum
N6+5=n-10
n6=n-15
n5=-15
n=-3
hope this helps:)
Answer:
No
Step-by-step explanation:
Pythagorean Theorem is "a^2+b^2=c^2"
Step 1) 1^2+6^2=37
37=c^2
Step 2) The square root of 37 is 6.08
That's not 9
So they don't form a Pythagorean triple
Answer is (x - 2).
<em>-</em><em> </em><em>BRAINLIEST</em><em> answerer</em>
