What 1-3+9 answe pleaseeeeeee

Mathematics

1 answer:

Bad White [126]2 years ago

6 0

That answer will be 7.
Explanation:
=1-3+9
=10-3
=7

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On a average day a horse might drink 50 la sheep might drink 4 l and a chicken might drink 200ml how much water would a farm wit

horsena [70]

Horse- 50l
sheep-4l
chicken-200ml

first you have to convert all the symbols into one, so we'll convert liters into milliliters,

1000ml=1l

horse= 50 ×1000=50000ml
sheep=4×1000=4000ml
chicken= 200ml

so now we have to multiply them by the number of animals,

h=50000ml×3=150000ml
s=4000×15=60000ml
c=200×12=2400ml

now add them together,

150000+60000+2400=212400ml

convert it into litres,
212400÷1000=212.4l

answer= 212.4 l

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The plan of a park is at a scale of 1:5000. Calculate the actual distance between two points if the distance between two points

andreyandreev [35.5K]

Multiple each of those by 5000, getting 35000, 14000, and 10000

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3 years ago

Find the slope of the line graphed below.

lozanna [386]

Answer:

slope is 7/3

Step-by-step explanation:

rise/run

7/3

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2 years ago

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The manager wants to advertise that anybody who isn't served within a certain number of minutes gets a free hamburger. But she d

aksik [14]

Answer:

The number of minutes advertisement should use is found.

x ≅ 12 mins

Step-by-step explanation:

(MISSING PART OF THE QUESTION: AVERAGE WAITING TIME = 2.5 MINUTES)

For such problems, we can use probability density function, in which probability is found out by taking integral of a function across an interval.

Probability Density Function is given by:

$f(t)=\left \{ {{0 ,\-t$

Consider the second function:

$f(t)=\frac{e^{-t/\mu}}{\mu}\\$

Where Average waiting time = μ = 2.5

The function f(t) becomes

$f(t)=0.4e^{-0.4t}$

The manager wants to give free hamburgers to only 1% of her costumers, which means that probability of a costumer getting a free hamburger is 0.01

The probability that a costumer has to wait for more than x minutes is:

$\int\limits^\infty_x {f(t)} \, dt= \int\limits^\infty_x {}0.4e^{-0.4t}dt$