Answer:
C
Step-by-step explanation:
 
        
             
        
        
        
The prime factorization of 6000<span> = 2^4</span>•3•5^3.
<span>The prime factors of </span>6000<span> are 2, 3 and 5.</span>
        
             
        
        
        
Answer:
<h2>20</h2>
<em>Solution</em><em>,</em>
<em><</em><em>N=</em><em>1</em><em>8</em><em>0</em><em>-</em><em>5</em><em>3</em><em>-</em><em>4</em><em>4</em>
<em> </em><em> </em><em> </em><em> </em><em>=</em><em>8</em><em>3</em>
<h3>
<em>Apply </em><em>sines </em><em>rule,</em></h3>
<em> </em>
</em>
<em>hope </em><em>this </em><em>helps.</em><em>.</em>
<em>Good </em><em>luck</em><em> on</em><em> your</em><em> assignment</em><em>.</em><em>.</em>
 
        
                    
             
        
        
        
Answer:
The height of the pole is 167 m
Step-by-step explanation:
The given parameters are;
Increase  in the length of the shadow = 90 m
Initial angle of elevation of the Sun = 58°
Final angle of elevation of the Sun = 36°
We have a triangle formed by the change in the length of the shadow and the rays from the two angle of elevation to the top of the pole giving an angle 22° opposite to the increase  in the length of the shadow  
We have by sin rule;
90/(sin (22°)  = (Initial ray from the top of the pole to the end of the shadow's length)/(sin(122°)
Let the initial ray from the top of the pole to the end of the shadow's length = l₁
90/(sin (22°)  = l₁/(sin(122°)
l₁ = 90/(sin (22°) ×(sin(122°) = 283.3 m
Therefore; 
The height of the pole = 283.3 m × sin(36°) = 166.52 m
The height of the pole= 167 m to three significant figures.