Answer:
they are -6 and -7
Step-by-step explanation:
Answer:
y = 2x + 5
Step-by-step explanation:
thats your graph: tell me of somethings wrong with the picture or you need anything else
Let's define variables:
s = original speed
s + 12 = faster speed
The time for the half of the route is:
60 / s
The time for the second half of the route is:
60 / (s + 12)
The equation for the time of the trip is:
60 / s + 60 / (s + 12) + 1/6 = 120 / s
Where,
1/6: held up for 10 minutes (in hours).
Rewriting the equation we have:
6s (60) + s (s + 12) = 60 * 6 (s + 12)
360s + s ^ 2 + 12s = 360s + 4320
s ^ 2 + 12s = 4320
s ^ 2 + 12s - 4320 = 0
We factor the equation:
(s + 72) (s-60) = 0
We take the positive root so that the problem makes physical sense.
s = 60 Km / h
Answer:
The original speed of the train before it was held up is:
s = 60 Km / h
Answer:
a. 
b. 
c. x=26; y=24 or (24,26)
Step-by-step explanation:
Let x = number of teachers hired.
Let y = number of tutors hired.
Now solving for part a we get
a. Write an inequality that represents the statement that the number of teachers hired must exceed the number of tutors hired.

solving for part b we get;
b. Write an inequality that represents the statement that the maximum number of teachers and tutors is 50.

solving for part c we get;
c. Choose a point that satisfies the situation, and explain why you chose that number of tutors and teachers.
Now we know that
also 
x=26; y=24
(24,26)
Explanation: To make number of teacher more than number of tutors this is the maximum value we can achieve for the requirement.