<span>The answer is 167 milliliters of 7% solution and 333 milliliters of 4% solution x + y = 500 x = 500 - y 0.07x + 0.04y = 25 (substitute 500 - y for x) 0.07(500 - y) + 0.04y = 25 35 - 0.07y + 0.04y = 25 -0.03y + 35 = 25 -0.03y = -10 y = 333.333... y [ = about 333 x = 500 - y = 500 - 333 = 167 hope it helps </span>
Answer:
Question 6: 26 crowns plus 15 ribbons.
Question 7: 10 footballs plus 42 basketballs.
Step-by-step explanation:
Question 6 explanation: Since the expression is 22 crowns plus 13 ribbons plus 2 ribbons plus 4 crowns, you can think of the different items as variables in an equation. Picture crowns are the variable
, and ribbons as the variable
, this will help you solve the equation in an easier way that allows you to comprehend each step better. The equation will now be
, in order to find how many
(crowns) and
(ribbons) you have, you need to combine like terms in the expression. In other words, add the terms with the variable
together, and add the terms with the variable
together. Simplified, the equation will be
. Since the variables
and
were used to represent crowns and ribbons respectively, that means the correct answer is 26 crowns plus 15 ribbons.
Question 7 explanation: You can use the same method as you did in question 6, think of footballs and basketballs as the variables
and
respectively. The equation will be
=
. Since the variable
was used to represent footballs and the variable
was used to represent basketballs, that means the correct answer would be 10 footballs plus 42 basketballs.
Answer:
a) The probability that this whole shipment will be accepted is 30%.
b) Many of the shipments with this rate of defective aspirin tablets will be rejected.
Step-by-step explanation:
We have a shipment of 3000 aspirin tablets, with a 5% rate of defects.
We select a sample of size 48 and test for defectives.
If more than one aspirin is defective, the batch is rejected.
The amount of defective aspirin tablets X can be modeled as a binomial distribution random variable, with p=0.55 and n=48
We have to calculate the probabilities that X is equal or less than 1: P(X≤1).

Answer:
45-40
Step-by-step explanation:
The first interval is 15-19.
The width of this interval is: 19-15=4
The second interval is 30-34.
The width of this interval is: 34-30=4
The third interval is 40-45.
The width of this interval is: 45-40=5
The fourth interval is 45-49.
The width of this interval is: 49-45=4
<h3>Therefore the interval that is not equal to the other three is 45-40</h3>