We can use Pythagorean's Theorem in order to find the remaining side length
a^2+b^2=c^2
Let a be the shadow length
Let b be the height of the flagpole
Let c be the hypotenuse
28^2+b^2=35^2
784+b^2=1225
b^2=1225-784
b^2=441
b=√441
b=21
Therefore the flagpole is 21 meters tall.
Hope this helps!
First find the critical points of <em>f</em> :
so the point (1, 0) is the only critical point, at which we have
Next check for critical points along the boundary, which can be found by converting to polar coordinates:
Find the critical points of <em>g</em> :
where <em>n</em> is any integer. We get 4 critical points in the interval [0, 2π) at
So <em>f</em> has a minimum of -7 and a maximum of 299.
Answer:
It's 6.
Step-by-step explanation:
6- 1, 2, 3, <u>6</u>
36- 1, 2, 3, 4, <u>6</u>
Answer
12855.04 ft³
Step-by-step explanation:
regular Octagon consists of 8 congruent triangles
B = (13.28 x 11) / 2 x 8=584.32
V = BH = 584.32 x 22 = 12855.04
Answer:
x² + (y + 8)² = 81
Step-by-step explanation:
Centre (h,k) = (0,-8)
radius (r) = 9
(x - h)² + (y - k)² = r²
(x - 0)² + (y + 8)² = 9²
x² + (y + 8)² = 81
