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mrs_skeptik [129]
3 years ago
5

If the area of a trapezoid is 28 m with a height of 14 m in with one of the base being 1 m to find the length of the second face

Mathematics
1 answer:
In-s [12.5K]3 years ago
4 0
The area of a trapezoid is basically the average width times the altitude, or as a formula:
Area = h ·

b 1 + b 2
2


where
b1, b2 are the lengths of each base
h is the altitude (height)
Recall that the bases are the two parallel sides of the trapezoid. The altitude (or height) of a trapezoid is the perpendicular distance between the two bases.

In the applet above, click on "freeze dimensions". As you drag any vertex, you will see that the trapezoid redraws itself keeping the height and bases constant. Notice how the area does not change in the displayed formula. The area depends only on the height and base lengths, so as you can see, there are many trapezoids with a given set of dimensions which all have the same area.
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3 years ago
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kondor19780726 [428]

The segment to draw is segment UT

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A line segment is a part of a line that is bounded by two two distinct  end points. In this case, segment UT is bounded by endpoints U and T. In the diagram, point R is not a segment but a point of intersection of segments BT and EU.

Learn More

Construction of a line segment: brainly.com/question/9716065

Keywords : proof, statement, reason, segments, reflexive property

#LearnwithBrainly

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3 years ago
2*2<br><img src="https://tex.z-dn.net/?f=%20%5Ccos%28300%29%20" id="TexFormula1" title=" \cos(300) " alt=" \cos(300) " align="ab
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Step-by-step explanation:

\cos(300 \degree)  \\  \\  = \cos(360 \degree - 60\degree)  \\  \\  = \cos( 60\degree) \\  \\  =  \frac{1}{2}  \\  \\  \huge \orange{ \boxed{ \therefore \: \cos(300 \degree)  = \frac{1}{2}  }}

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