All categories

3 years ago

Is 1.875 an rational or irrational number

Mathematics

2 answers:

sladkih [1.3K]3 years ago

5 0

Rational ! hope this helps :)

vazorg [7]3 years ago

5 0

Answer:

it is rational

Step-by-step explanation:

because our is a finite decimal which can be converted into a fraction

You might be interested in

Using b=1+r, what does b=

alisha [4.7K]

Answer:

Adding 12 to the circle area is equal to the square area.

s2 = 12 + A

Where

s = side of square

A = area of circle

s2 = 12 + 36

s2 = 48

Solve this for s to get the side length

4 0

3 years ago

A clerk is marking up merchandise 34%. The original price of an item is $455. What will be the retail price?

Nadusha1986 [10]

To find markup price, multiply the original number (455) by 1 + the decimal equivilent of the percent increase (.34)
so
455*1.34= $609.70

4 0

3 years ago

Read 2 more answers

A circular cake is cut into 8 equal pieces. What is the angle measure of each piece?

pishuonlain [190]

Answer:

Step-by-step explanation:

A whole circle is 360 so if you divided that by 8 you get 45

4 0

3 years ago

Read 2 more answers

Given that ∠ABC ≅ ∠DBE, which statement must be true?

Gala2k [10]

Line Segment AB ≅ Line Segment DB

6 0

3 years ago

Read 2 more answers

Find the derivative.

krek1111 [17]

Answer:

$\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

General Formulas and Concepts:

Algebra I

Terms/Coefficients

Expanding/Factoring

Calculus

Differentiation

Derivatives
Derivative Notation

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Rule [Quotient Rule]: $\displaystyle \frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

Identify

$\displaystyle f(x) = \frac{\sqrt{x}}{e^x}$

Step 2: Differentiate

Derivative Rule [Quotient Rule]: $\displaystyle f'(x) = \frac{(\sqrt{x})'e^x - \sqrt{x}(e^x)'}{(e^x)^2}$
Basic Power Rule: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}(e^x)'}{(e^x)^2}$
Exponential Differentiation: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{(e^x)^2}$
Simplify: $\displaystyle f'(x) = \frac{\frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x}{e^{2x}}$
Rewrite: $\displaystyle f'(x) = \bigg( \frac{e^x}{2\sqrt{x}} - \sqrt{x}e^x \bigg) e^{-2x}$
Factor: $\displaystyle f'(x) = \bigg( \frac{1}{2\sqrt{x}} - \sqrt{x} \bigg)e^\big{-x}$

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

7 0

2 years ago