Answer:
it will be (x-9)(x-3)
Step-by-step explanation:
hope this helped
A slope of -3 can be written as a fraction of -3 over 1.
In terms of rise over run, that means when we subtract 3 from y we add 1 to x.
So plot (1, 3), then go down 3 and over 1 and plot that point.
Make a line between them and you're done.
Answer:
f(n) = -11 + 22(n - 1)
<em>f(1) is your initial value.</em>
f(1) = -11 + 22(1 - 1)
f(1) = -11
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f(2) = -11 + 22(2 - 1) = 11
f(3) = -11 + 22(3 - 1) = 33
f(4) = -11 + 22(4 - 1) = 55
<em>f(n - 1) is just a notation for the previous term</em>
<em>Using the equation f(n) = f(n - 1) + _______ :</em>
f(2) = f(1) + ??? = 11
f(3) = f(2) + ??? = 33
f(4) = f(3) + ??? = 55
f(2) = -11 + ??? = 11
f(3) = 11 + ??? = 33
f(4) = 33 + ??? = 55
f(2) = -11 + 22 = 11
f(3) = 11 + 22 = 33
f(4) = 33 + 22 = 55
∴ f(n) = f(n - 1) + 22
.
Two points on the graph of the linear function f are (0,3) and (3,9). Write a function g whose graph is a reflection in the x-axis of the graph of f
Answer:
mhm
Step-by-step explanation:
