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LiRa [457]
3 years ago
11

Olivia and Camille went clothes shopping. Camille spent $19.40 less than twice what Olivia spent. In total, they spent $272.35.

find the amount each girl spent.
Mathematics
1 answer:
nydimaria [60]3 years ago
4 0

if Camille spent 19.40$ LESS than DOUBLE what Olivia spent then a rough estimate already can be Olivia spent 100 and Camille spent 172 but to find this out we have to add 19.40 onto 272.35 = 291.75 then we now that 291.75 is thrice what Olivia spent so if we third it we know what Olivia spent so 291.75/3 = 97.25 leaving 194.50 then if we minus 19.40 off 194.50 we get 175.10 so:

Camille spent: 175.10 and

Olivia Spent: 97.25

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3 years ago
A and B are partner in a business .A contribution RS 20000 and B rs 30000 a however acts as a manager the understanding being th
Vesna [10]

Answer:

Rs 1,650

Step-by-step explanation:

The given contribution are;

<em>A</em> contributes Rs 20,000, and <em>B</em> contributes Rs 30,000

The percentage of the profit <em>A</em> receives as manager = 25%

The amount of the profit divided in the ratio of their contribution = The remaining profit (75%)

The amount <em>B</em> gets = Rs1,350

The amount <em>A</em> gets = required

The ratio of their contribution at which the remaining profit is shared = 20,000:30,000 = 2:3

Where, out of 5 parts of 75% of the profits, <em>B</em> gets 3, while <em>A</em> gets 2

Let <em>P</em> represent the profit, we have;

B's share = 3/5× 0.75 × P = 1,350

∴ P = (5 × 1,350/3)/0.75 = 3,000

<em>A</em> gets 25% of the profits and 2/5 of the 75% remaining profit

∴ The amount <em>A</em> gets = 0.25×3000 + (2/5)×0.75×3000 = 1,650

Or simply put;

<em>A</em> gets the remainder of the profit which is Rs 3,000 - Rs 1,350 = Rs 1,650

8 0
2 years ago
If you buy 3 tickets for 50 cents each and have $.40 left over , how many do u have before purchasing?
Pachacha [2.7K]

Answer:

Step-by-step explanation:

($0.50 * 3) + $0.40= $1.90

5 0
3 years ago
Read 2 more answers
Tomika heard that the diagonals of a rhombus are perpendicular to each other. Help her test her conjecture. Graph quadrilateral
Stella [2.4K]

Answer:

a. The four sides of the quadrilateral ABCD are equal, therefore, ABCD is a rhombus

b. The equation of the diagonal line AC is y = 5 - x

The equation of the diagonal line BD is y = 5 - x

c. The diagonal lines AC and BD of the quadrilateral ABCD are perpendicular to each other

Step-by-step explanation:

The vertices of the given quadrilateral are;

A(1, 4), B(6, 6), C(4, 1) and D(-1, -1)

a. The length, l, of the sides of the given quadrilateral are given as follows;

l = \sqrt{\left (y_{2}-y_{1}  \right )^{2}+\left (x_{2}-x_{1}  \right )^{2}}

The length of side AB, with A = (1, 4) and B = (6, 6) gives;

l_{AB} = \sqrt{\left (6-4  \right )^{2}+\left (6-1  \right )^{2}} = \sqrt{29}

The length of side BC, with B = (6, 6) and C = (4, 1) gives;

l_{BC} = \sqrt{\left (1-6  \right )^{2}+\left (4-6  \right )^{2}} = \sqrt{29}

The length of side CD, with C = (4, 1) and D = (-1, -1) gives;

l_{CD} = \sqrt{\left (-1-1  \right )^{2}+\left (-1-4  \right )^{2}} = \sqrt{29}

The length of side DA, with D = (-1, -1) and A = (1,4)   gives;

l_{DA} = \sqrt{\left (4-(-1)  \right )^{2}+\left (1-(-1)  \right )^{2}} = \sqrt{29}

Therefore, each of the lengths of the sides of the quadrilateral ABCD are equal to √(29), and the quadrilateral ABCD is a rhombus

b. The diagonals are AC and BD

The slope, m, of AC is given by the formula for the slope of a straight line as follows;

Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}

Therefore;

Slope, \, m_{AC} =\dfrac{1-4}{4-1} = -1

The equation of the diagonal AC in point and slope form is given as follows;

y - 4 = -1×(x - 1)

y = -x + 1 + 4

The equation of the diagonal AC is y = 5 - x

Slope, \, m_{BD} =\dfrac{-1-6}{-1-6} = 1

The equation of the diagonal BD in point and slope form is given as follows;

y - 6 = 1×(x - 6)

y = x - 6 + 6 = x

The equation of the diagonal BD is y = x

c. Comparing the lines AC and BD with equations, y = 5 - x and y = x, which are straight line equations of the form y = m·x + c, where m = the slope and c = the x intercept, we have;

The slope m for the diagonal AC = -1 and the slope m for the diagonal BD = 1, therefore, the slopes are opposite signs

The point of intersection of the two diagonals is given as follows;

5 - x = x

∴ x = 5/2 = 2.5

y = x = 2.5

The lines intersect at (2.5, 2.5), given that the slopes, m₁ = -1 and m₂ = 1 of the diagonals lines satisfy the condition for perpendicular lines m₁ = -1/m₂, therefore, the diagonals are perpendicular.

5 0
3 years ago
Need help asap
Archy [21]
Start by writing it out like this. there are no missing values. do you need help solving?

7 0
3 years ago
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