Graph any third-degree polynomial (a cubic graph) that has exactly one x-intercept, a relative/global minimum at (-2.1), and a r
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The line has a positive slope. Let's look at all the slopes:
1) -3
2) -3
3) 3
4)3
Which ones are positive? That's right, 3 and 4. We don't know which equation would be the equation of the line. That's where the other information comes in.
The line intersects the y-axis at at a point that has a negative y-coordinate. Lets write the last two equations in slope-intercept form.
1) y = -3/2x - 5/2
2) y = -3/2x + 5/2
We have to graph both of the lines now. The graphs are at the very bottom. Take a look at them. In the first one, the y-intercept is a negative and in the second one, the y-intercept is positive.
The third one AKA 3x + 2y = -5 is the equation of the line. I hope this helps! Let me know if I got it wrong or if you need any more help.
