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oksian1 [2.3K]
3 years ago
7

Find the value of this fraction computation: 6(1/2 + 2/3 + 3/4) Show the steps.

Mathematics
1 answer:
Marta_Voda [28]3 years ago
7 0

6(1/2 + 2/3 + 3/4)

= 6(1/2) + 6(2/3) + 6(3/4)

= 3 + 4 + 4 1/2

= 11 1/2

Answer

11 1/2  (23/2 or 11.5)


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A forester studying the effects of fertilization on certain pine forests in the Southeast is interested in estimating the averag
ahrayia [7]

Answer:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(ZStep-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the area of a population, and for this case we know the distribution for X is given by:

X \sim N(M,4)  

Where \mu=M and \sigma=4

We select a a sample of n =4 and since the distribution for X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we want to find this probability:

P(-2 \leq \bar X -\mu \leq 2)

If we divide both sides by \frac{\sigma}{\sqrt{n}} we got:

P(\frac{-2}{\frac{4}{\sqrt{9}}}\leq Z \leq \frac{2}{\frac{4}{\sqrt{9}}})

And we can use the normal distribution table or excel to find the probabilites and we got:

P(-1.5 \leq Z \leq 1.5)= P(Z

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Answer:

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Step-by-step explanation:

:/

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Answer:

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Step-by-step explanation:

Definition of absolute value:

|a| = a if a ≥ 0

|a| = -a if a < 0

Examples:

|2| = 2

|-2| = -(-2) = 2

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|-0.45| = -(-0.45) = 0.45

|1000| = 1000

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|1.7| = 1.7

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