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3 years ago

I need help now plz !

Mathematics

1 answer:

My name is Ann [436]3 years ago

8 0

Answer:D

Step-by-step explanation:

students playing trombone=12+10+7+16

Students playing trombone=45

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A travel website sells tickets to a city for two airlines. Among those buying tickets, 20% fly airline A, and 80% fly airline B.

Naddika [18.5K]

Answer:

The expected revenue of an airline ticket sold by this travel website is $408

Step-by-step explanation:

For the revenues per ticket we have;

airline A; 600

airline B; 360

For the probability of choosing the airlines we have;

airline A; 20% = 0.2

airline B; 80% = 0.8

Therefore, the expected revenue of an airline ticket sold by this travel website is;

600(0.2) + 360(0.8) = 408

Therefore, the expected revenue of an airline ticket sold by this travel website is $408

7 0

3 years ago

What are the solutions to the equation 2(x-3)^2=54 ?

erastova [34]

Answer:

x =(6-√108)/2=3-3√ 3 = -2.196

x =(6+√108)/2=3+3√ 3 = 8.196

Step-by-step explanation:

Step 1 :

Equation at the end of step 1 :

2 • (x - 3)2 - 54 = 0

Step 2 :

2.1 Evaluate : (x-3)2 = x2-6x+9

Step 3 :

Pulling out like terms :

3.1 Pull out like factors :

2x2 - 12x - 36 = 2 • (x2 - 6x - 18)

Adding 9 has completed the left hand side into a perfect square :

x2-6x+9 =

(x-3) • (x-3) =

(x-3)2 (x-3)1 =

x-3

Now, applying the Square Root Principle to Eq. #4.3.1 we get:

x-3 = √ 27

Add 3 to both sides to obtain:

x = 3 + √ 27

Since a square root has two values, one positive and the other negative

x2 - 6x - 18 = 0

has two solutions:

x = 3 + √ 27

x = 3 - √ 27

Solve Quadratic Equation using the Quadratic Formula

4.4 Solving x2-6x-18 = 0 by the Quadratic Formula .

According to the Quadratic Formula, x , the solution for Ax2+Bx+C = 0 , where A, B and C are numbers, often called coefficients, is given by :

- B ± √ B2-4AC

x = ————————

In our case, A = 1

B = -6

C = -18

Accordingly, B2 - 4AC =

36 - (-72) =

108

Applying the quadratic formula :

6 ± √ 108

x = —————

Can √ 108 be simplified ?

Yes! The prime factorization of 108 is

2•2•3•3•3

To be able to remove something from under the radical, there have to be 2 instances of it (because we are taking a square i.e. second root).

√ 108 = √ 2•2•3•3•3 =2•3•√ 3 =

± 6 • √ 3

√ 3 , rounded to 4 decimal digits, is 1.7321

So now we are looking at:

x = ( 6 ± 6 • 1.732 ) / 2

Two real solutions:

x =(6+√108)/2=3+3√ 3 = 8.196

or:

x =(6-√108)/2=3-3√ 3 = -2.196

7 0

3 years ago

HELP ME PLEASEEEEEEEEEEE

hichkok12 [17]

Answer:

The perimeter is 16 units

Step-by-step explanation:

Add up all the sides together

1+1+7+7 = 16

6 0

3 years ago

Read 2 more answers

What is a y-intercept of the graphed function?

Flura [38]

(0,-9) is the y intercept

8 0

3 years ago

6. If you draw 35 lines on a piece of paper so that no two lines are parallel to each

umka2103 [35]

The point of intersection is the point where lines intersect.

There will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Given

$n = 35$ --- the number of lines

$d = 3$ --- no three lines are concurrent

When no three line are concurrent, it means that no three lines meet at the same point.

So, the sequence of intersection is:

0 intersection for 1 line
1 intersection for 2 lines
3 intersections for 3 lines
6 intersections for 4 lines

Following the above sequence, the number of intersections for n lines is:

$n_k = \frac{n \times (n - 1)}{2}$

In this case, $n = 35.$

So, we have:

$n_k = \frac{35 \times (35 - 1)}{2}$

$n_k = \frac{35 \times 34}{2}$

$n_k = 35 \times 17$

$n_k = 595$

Hence, there will be 595 intersections for 35 lines, where no 3 lines are concurrent.

Read more about lines of intersections at:

brainly.com/question/22368617

7 0

2 years ago

Read 2 more answers