Answer:
R-{-5}
Step-by-step explanation:
you get the vertex by making the denominator =0
ex.z+5=0 ,z=-5
then we see if the rational function has a constant beside it ex. 3÷z+5-3 ,but in this you Don't have one so its 0
so the vertex would be (-5,0)
the domain =R-{-5} , range=R-{0}
This is true. There is no question connected which is why there are no answers!
Answer:
Step-by-step explanation:
Given the equation y=-2x+1 and given another equation y=mx+b in order for us to have no solution we must guarantee that both lines do not intersect. Recall that m is the slope of the second equation and b the y-intercept. To guarantee that both lines don't intersect, they must be parallel. To have this result, we must have that they have the same slope but different y intercept. That is take m = -2 and b any value different to +1. For example, the b = 6. So
y = -2x+6 = -2(x-3) is another equation that gives no solution to the system.
Since FA || BE, then angle 1 must equal angle 2 since they are corresponding angles along parallel lines where the transverse line cuts.
Thus, if angle 1 is 59, then angle 2 must also be 59 (ie D)
Answer:
4x-6y
Step-by-step explanation:
