The correct answer to this question is this one:
find the energy of one photon:
<span>E=h*<span>c/λ
</span></span>
divide the energy given by the energy of one photon of that wavelength
What I've done so far is convert wave length to m and energy to j.
E photon = h * x / wave length
E = (6.626 x 10^-43)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^18 J
3.38 x 10 ^18 J x 1000 kj / 1 j = 3.37 x 10 ^ 16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 16
E = (6.626 x 10^-34)(3.00 x 10^8) / 587 ^ -9 = 3.38 x 10 ^19 J
3.38 x 10 ^19 J x 1000 kj / 1 j = 3.37 x 10 ^ -16 Kj
609 kJ/ 3.37 x 10 ^ 16 Kj = 1.81 x 10 ^ 18 but the answer is 1.81 × 10^24 photons
3.38 x 10 ^-19 J
should be negative
then 3.38 x 10 ^18 J x 1kJ/1000 J
you're converting from J to kJ.. just like meters to kilometres, you wouldn't multiply you would divide
Answer:The density of ammonia (
) at 273 K and 1.00 atm is 0.75 g/L.
Explanation:
Temperature of the gas = T = 273 k
Pressure exerted by the gas,P = 1.00 atm
Volume occupied by the gas = V
Number of moles of gas = n
PV=nRT (Ideal gas equation)


Density of the gas:

The density of ammonia (
) at 273 K and 1.00 atm is 0.75 g/L.
IT IS NOT POSSIBLE TO RETRIEVE A BOTTLE OF SULFATE BECAUSE SULFATE DOES NOT EXIST AS A DISTINCT CHEMICAL COMPOUND.
Sulphate is a polyatomic ion. A polyatomic ions refers to group of atoms that carry charges. Sulfate carries a charge of +2. Sulfate is a very reactive ion, thus, it can not be found existing on its own, it is always found in combination with other elements, such elements include H2SO4 and CaSO4.
Answer:
7.22*10^24 molecules
Explanation:
Since one mole has 6.02*10^23 you'd multiply that number by 12
that equals 7.224*10^24 but you need sig figs