Question

A solution is created by dissolving 11.0 grams of ammonium chloride in enough water to make 235 mL of solution. How many moles of ammonium chloride are present in the resulting solution

Answer 1

Answer:

The correct answer is 0.206 moles

Explanation:

According to the given scenario, the calculation of the number of moles of ammonium chloride is available in the resulting solution is given below:

Given that

Amount of $NH_4Cl$ is 11.0 grams

And, the volume is 235 mL

Now the molar mass of $NH_4Cl$ is 53.49g/mol

So, the number of moles presented is

= 11.0 ÷ 53.49

= 0.206 moles

hence, the number of moles of ammonium chloride are available in the resulting solution is 0.206 moles