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Olenka [21]
3 years ago
6

Haley's work evaluating (-2) is shown below.

Mathematics
2 answers:
AveGali [126]3 years ago
7 0

Answer:

(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2) = 256

Step-by-step explanation:

Since there is an even number of negative numbers, the product is positive.

(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2) = 256

If this answer is correct, please make me Brainliest!

lilavasa [31]3 years ago
7 0

Answer:

(-2)(-2)(-2)(-2)(-2)(-2)(-2)(-2) = 256

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Svetach [21]

Answer:

Because she is concluding that her class is an accurate representation of the overall school. The sample size in this case is too small and should increase her sample size(the amount of people surveyed) in order to get a better result.

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3 years ago
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Vesnalui [34]

Answer:

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Step-by-step explanation:

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3 years ago
Read 2 more answers
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yulyashka [42]

Answer:

Option 1: 1430p + 2200 = -4001

Step-by-step explanation:

Given that:

1.43p + 2.2 = -4.001

We can replace:

1.43p by 1430p * 10^-3

2.2 by 2200 * 10^-3

-4.001 by -4001* 10^-3

So the equation will become:

1430p * 10^-3 + 2200* 10^-3 = -4001 * 10^-3

Taking  10^-3 common from both side

(1430p + 2200)* 10^-3 = -4001 * 10^-3

Cancelling  10^-3 from both sides we get:

1430p + 2200 = -4001

3 0
3 years ago
A restaurant has an electronic system that randomly selects customers when they pay for their meal to
polet [3.4K]

Using the binomial distribution, it is found that there is a 0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

For each customer, there are only two possible outcomes, either they receive the coupon, or they do not. The probability of a customer receiving the coupon is independent of any other customer, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • For each customer, 10% probability of receiving a coupon, thus p = 0.1.
  • 2 customers are selected, thus n = 2

The probability that <u>neither receives a coupon is P(X = 0)</u>, thus:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2,0}.(0.1)^{0}.(0.9)^{2} = 0.81

0.81 = 81% probability that NEITHER customer is selected to receive a coupon.

A similar problem is given at brainly.com/question/25326823

7 0
3 years ago
-30p/(10p-4p) simplify
melomori [17]
-30p/6p
-5p is the answer

First you do solve the numbers in the parenthesis. Then divide the two numbers to get -5p
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4 years ago
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