Consecutive prime numbers are going to be close to one another in the number line, and therefore not very different from the square of the number midway between them. We can thus try to locate the prime numbers in question by looking between the square root of 1000 (31.6) and 1500 (38.7). <span>In this immediate vicinity, the only prime numbers are 31 and 37, which are consecutive - no other prime numbers lie between them. The product of 31 and 37 is 1147, which is between 1000 and 1500. This meets the description above, so Martiza's PIN must be 1147.
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The answer to 4(y+6) is 4y+24
C is the correct answer
$25 is constant and $1.30 is the variable cost that changes per day, therefore it would be $25 + (1.3×No. of Days)
Answer:
Step-by-step explanation:
Important Information:
Perimeter of rectangle=
Method:
The first step to work this out is to multiply the width of 85 by 2, this gives you 170.This is because a rectangle has two sets of equal sides. This means that there two widths.
The next step is to subtract 170 from the perimeter of 364, this gives you 194. This is because the formula for the perimeter of a rectangle is. This means that in order to isolate the values of the lenght we must subtract the values of the width.
The final step is to divide the value of 194 by 2, this gives you 97. This is because that is the value for 2*the length. That means in order to work out the value of 1 you would need to divide by 2.
Step By Step:
1) Multiply 85 by 2.
2) subtract 170 from 364.
3) Divide 194 by 2.
Answer:
There is obviously only 1 10x10 square. If we start with a 9x9 square in the top left corner, we can move it down 1, across 1 and back up 1, so there are 4 possible 9x9 squares.
For 8x8 we can move down 1, then 2 and we can move across 1 or 2 so that's 9 possible 8x8 squares.
For 7x7 we can go down 3 and across 3, so that's 4x4=16 possible squares.
The pattern is now clear the total number if squares is 1+4+9+16+…+100.
There's a formula for this, which I had to look up, but any the sum of the first n squared is 1/6n(n+1)(2n+1)1/6n(n+1)(2n+1), so the total number of squares is 10x11x21/6=5x11x7=385.
