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Serga [27]
3 years ago
12

When written in standard form, the leading coefficient of the equation of a parabola that opens up will be- a fraction zero a wh

ole number negative an integer positive
Mathematics
1 answer:
kirill115 [55]3 years ago
8 0

Answer:

Positive integer

Step-by-step explanation:

A parabola is the locus of a point which is equidistant from a fixed point and a fixed line. The fixed line is known as the directrix, while the fixed point is known as the focus.

The axis of a parabola passes through the focus and is perpendicular to the directrix. The axis touches the parabola at a point known as the vertex.

The standard form of a parabola that opens up is:

4ay = x²;

where the focus is at (0, a), the equation of the axis is x = 0 and the equation of the directrix is y = -a (parallel to the y axis).

Hence, the leading coefficient of the equation of a parabola that opens up will be a positive integer.

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Answer:

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7 0
3 years ago
Answer the attached question ASAP!!!​
ch4aika [34]
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6 0
2 years ago
Solve the equation <br>r ÷ (-8) =5​
krok68 [10]

Answer:

r=-40

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
Prove the following statement.
gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form 2k+1 where k\in \mathbb{Z}. Consider the following cases.

Case 1. If k is even we have: (2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1.

If we denote by m=2s^2+2 we have that (2k+1)^{2}=8m+1.

Case 2. if k is odd we have: (2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1.

If we denote by m=2s^{2}+24s+1 we have that (2k+1)^{2}=8m+1

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

6 0
2 years ago
19 squared equals 361
Fudgin [204]
Correct, I am not sure it that was the answer you were looking for
6 0
3 years ago
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