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Lunna [17]
3 years ago
14

Jodi traded $3400 for Chinese yuan, immediately changed her mind, and then

Mathematics
2 answers:
viktelen [127]3 years ago
8 0

Answer: C hope this helps :)!

Dima020 [189]3 years ago
8 0

Answer:

C. More than $0 but less than $3400

Step-by-step explanation:

Logically one may think that if the exchange rate doesn't change then Jodi would get the same amount of money back that she traded. The key part of the question is which amount is she "most likely" to have. Almost all exchanges require flat fees in order to accommodate workers and trading. Jodi would probably get most of her money back, but not all $3400 dollars.

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A woman is randomly selected from the 18–24 age group. For women of this group, systolic blood pressures (in mm Hg) are normally
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Answer:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

And we can find this probability using the complement rule:

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Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(114.8,13.1)  

Where \mu=114.8 and \sigma=13.1

We are interested on this probability

P(X>140)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:P(X>140)=P(\frac{X-\mu}{\sigma}>\frac{140-\mu}{\sigma})=P(Z>\frac{140- 1114.8}{2.6})=P(z>1.924)And we can find this probability using the complement rule:

P(z>1.924)=1-P(z

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Step-by-step explanation:

Tell me if I’m wrong

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Step-by-step explanation:

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There's no way to tell if we can't see the inequality.

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