Answer:
solution
given that
ar=8 __________equation 1
r=4
putting r=4in equation 1 we get
a×4=8
a=2
now
t4=ar^(4-1)
= 2×4^3
=2×4×4×4
=128ans
Answer:
I18 - xI such that x < 18.
ok, first let's what happens if x = 18:
I18 - xI = I18 - 18I = 0
So, at the moment we have the condition:
I18 - xI > 0.
now, if x is a really large negative number, suppose, x = -100
I18 + 100I = I118I = 118
So, as x can freely move in the negative range, we can see that I18 - xI can be any positive number, so the only restriction that we have is:
I18 - xI > 0.
This means that the domain is:
D = (-∞, 18)
and the range is:
R = (0, ∞)
Answer:
81π
Step-by-step explanation:
-The sum of central angles in a circle add up to 360°.
-Let x be the area of the circle.
-Given the area of a 120° is 27π, the circles area can be calculated as:

Hence, the area of the circle is 81π
Answer:
B) 7.5 in3
Step-by-step explanation:
If you divide 21/49 by 7 you get 3/7