Answer:
4 km per hour and 6 km per hour.
Step-by-step explanation:
The combined running rate = 30/3 = 10 km/h.
If one runner's speed = x then the other one's speed is x+2 km/h.
So x + x + 2 = 10
2x = 8
x = 4
So one runs at 4 km/h and the other at 6 km/h.
Answer:
$1.80
Step-by-step explanation:
2/3x = 1.2
x = 1.2 / (2/3)
x = 1.2 * (3/2)
x = 1.80
Answer:
y = 3sin2t/2 - 3cos2t/4t + C/t
Step-by-step explanation:
The differential equation y' + 1/t y = 3 cos(2t) is a first order differential equation in the form y'+p(t)y = q(t) with integrating factor I = e^∫p(t)dt
Comparing the standard form with the given differential equation.
p(t) = 1/t and q(t) = 3cos(2t)
I = e^∫1/tdt
I = e^ln(t)
I = t
The general solution for first a first order DE is expressed as;
y×I = ∫q(t)Idt + C where I is the integrating factor and C is the constant of integration.
yt = ∫t(3cos2t)dt
yt = 3∫t(cos2t)dt ...... 1
Integrating ∫t(cos2t)dt using integration by part.
Let u = t, dv = cos2tdt
du/dt = 1; du = dt
v = ∫(cos2t)dt
v = sin2t/2
∫t(cos2t)dt = t(sin2t/2) + ∫(sin2t)/2dt
= tsin2t/2 - cos2t/4 ..... 2
Substituting equation 2 into 1
yt = 3(tsin2t/2 - cos2t/4) + C
Divide through by t
y = 3sin2t/2 - 3cos2t/4t + C/t
Hence the general solution to the ODE is y = 3sin2t/2 - 3cos2t/4t + C/t
Answer:
12g8h10
Multiply each variable quantity by 2 and combine.
Answer:
I honestly don't know sry
Step-by-step explanation:
