X + 37 x + 67 90 104 14 -14 -7°

Mathematics

1 answer:

natulia [17]4 years ago

8 0

It would be 104? I don’t understand the question but I guessing you’re adding

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Can anyone help me with this ?

anygoal [31]

Answer:

The correct answer, pertaining to the proposed interrogate, is acknowledged as x = 3.

Step-by-step explanation:

To evaluate for such, a comprehension of linear data must be obtained:

Slope = rise/run, defined as the agglomerate distance between two differentiated points.

X-intercept: The peculiar point in which linear data is observed to intersect the x-axis.

Y-intercept: The peculiar point in which linear data is observed to intersect the y-axis.

If there is a vertical line intersecting the x-axis, the particular point (x, y) is identified as what x is equated to.

Likewise, if there is a horizontal line intersecting the y-axis, the particular point (x, y) is identified as what y is equated to.

Thus, the following must be applied to the interrogate:

- Vertical line, thus determine the point in which the data intersects the x-axis.

- Such is identified as (3,0).

Thus, since that is the only linear figure intersecting at such peculiar axis, 3 is the equated value of x.

Hence, x = 3.

*I hope this helps.

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3 years ago

Naomi wants to take fitness classes at a nearby gym, but she needs to start by selecting a membership plan. With the first membe

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54+x=12+3x
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3 years ago

Someone help??????????????

irina1246 [14]

I: x-2y>=8
II:2x+y<=3

start by isolating y on a side

with I:
x-2y>=8
-2y>=8-x
2y<=x-8
y<=x/2-4

with II:
2x+y<=3
y<=-2x+3

now you can draw I' and II' and read of the solutions with the graph.
transform the inequalities into lines in slope intercept form by replacing the inequality with equality:
y<=x/2-4
->
y=x/2-4

y<=-2x+3
->
y=-2x+3

look at the inequalities to figure out if the area above or below is valid for each line (y<=... -> area below is valid->colored in the attached image)
the area in which all areas overlap is the solution space.