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marissa [1.9K]
3 years ago
11

If you wanted to find out whether an integer contained an even number of 1 bits, which status flag would be useful

Computers and Technology
1 answer:
AleksandrR [38]3 years ago
8 0

Answer:

The correct answer will be "Parity".

Explanation:

  • Parity seems to be a methodology that tests when information is transferred or missing or overwritten when something is transferred between one storage location to another, and then it is communicated between processors or devices.
  • It would be used whilst also contrasting the container as well as the aggregated parity to evaluate or dual inspect for inaccuracies.
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1. Print out the string length of s1 2. Loop through characters in s2 with charAt() and display reversed string 3. Compare s2, s
konstantin123 [22]

Answer:

See explaination

Explanation:

public class StringLab9 {

public static void main(String args[]) {

char charArray[] = { 'C', 'O', 'S', 'C', ' ', '3', '3', '1', '7', ' ', 'O', 'O', ' ', 'C', 'l', 'a', 's', 's' };

String s1 = new String("Objected oriented programming language!");

String s2 = "COSC 3317 OO class class";

String s3 = new String(charArray);

// To do 1: print out the string length of s1

System.out.println(s1.length());

// To do 2: loop through characters in s2 with charAt and display reversed

// string

for (int i = s2.length() - 1; i >= 0; --i)

System.out.print(s2.charAt(i));

System.out.println();

// To do 3: compare s2, s3 with compareTo(), print out which string (s2 or s3)

// is

// greater than which string (s2 or s3), or equal, print the result out

if (s2.compareTo(s3) == 0)

System.out.println("They are equal");

else if (s2.compareTo(s3) > 0)

System.out.println("s2 is greater");

else

System.out.println("s3 is greater");

// To do 4: Use the regionMatches to compare s2 and s3 with case sensitivity of

// the first 8 characters.

// and print out the result (match or not) .

if (s2.substring(0, 8).compareTo(s3.substring(0, 8)) == 0)

System.out.println("They matched");

else

System.out.println("They DONT match");

// To do 5: Find the location of the first character 'g' in s1, print it out

int i;

for (i = 0; i < s2.length(); ++i)

if(s2.charAt(i)=='g')

break;

System.out.println("'g' is present at index " + i);

// To do 6: Find the last location of the substring "class" from s2, print it

// out

int index = 0, ans = 0;

String test = s2;

while (index != -1) {

ans = ans + index;

index = test.indexOf("class");

test = test.substring(index + 1, test.length());

}

System.out.println("Last location of class in s2 is: " + (ans + 1));

// To do 7: Extract a substring from index 4 up to, but not including 8 from

// s3, print it out

System.out.println(s3.substring(4, 8));

} // end main

} // end class StringLab9

7 0
3 years ago
Why are businesses willing to provide more goods at higher prices
irina1246 [14]
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3 years ago
The answer for 1 and 2
Mrrafil [7]
1. A.  It is basically the definition of a political cartoon.
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4 years ago
Can someone help me please
Andreyy89
Your anwser will be the last one
6 0
4 years ago
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Which of the following best explains how symmetric encryption are typically used?
Y_Kistochka [10]

A: Symmetric encryption uses a single key that should be kept secret. The same key is used for both encryption and decryption of data.

6 0
3 years ago
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