Answer:
Following are the program in the Python Programming Language.
#define function
def Transfer(S, T):
#set for loop
for i in range(len(S)):
#append in the list
T.append(S.pop())
#return the value of the list
return T
#set list type variable
S = ["a","b","c","d"]
#print the values of the list
print(S)
#set the list empty type variable
T=[]
#call the function
T = Transfer(S, T)
#print the value of T
print(T)
<u>Output:</u>
['a', 'b', 'c', 'd']
['d', 'c', 'b', 'a']
Explanation:
Here, we define the function "Transfer()" in which we pass two list type arguments "S" and "T".
- Set the for loop to append the values in the list.
- Then, we append the value of the variable "S" in the variable "T".
- Return the value of the list variable "T" and close the function.
- Then, set the list data type variable "S" and initialize the elements in it and print that variable.
- Finally, we set the empty list type variable "T" and store the return value of the function "Transfer()" in the variable "T" then, print the value of the variable "T".
Option A. is the correct answer the other three are not professional behaviour if you would like an explanation as to why they are not just comment
Answer:
TRUE
Explanation:
A rootkit is a collection of computer software, typically malicious, that is designed to grant an unauthorized user access to a computer or certain programs. Once a rootkit is installed, it is easy to mask its presence, so an attacker can maintain privileged access while remaining undetected.
Rootkit detection is difficult because a rootkit maybe able to subvert the software that is intended to find it.
Rootkits work by using a process called modification (the changing of user account permissions and security).
Rootkits are not malware themselves, but rather a process used to deploy malware on a target.
Therefore, it is TRUE that a rootkit is software and file folders that are hidden from view and permit viruses, spyware, and malware to be installed on a PC without the knowledge or consent of a user.
Answer:
<u>Call by reference</u>
In an function if the variables are passed as reference variables this means that the variables are pointing to the original arguments.So the changes made in the function on the reference variables will be reflected back on the original arguments.
For example:-
#include<stdio.h>
void swap(&int f,&int s)
{
int t=f;
f=s;
s =temp;
}
int main()
{
int n,m;
n=45;
m=85;
swap(n,m);
printf("%d %d",m,n);
return 0;
}
the values of m and n will get swapped.
<u>
Call by value</u>
In this program the values of m and n will not get swapped because they are passed by value.So duplicate copies of m and n will be created and manipulation will be done on them.
#include<stdio.h>
void swapv(int f,int s)
{
int t=f;
f=s;
s=temp;
}
int main()
{
int n,m;
n=45;
m=85;
swapv(n,m);
printf("%d %d",n,m);
return 0;
}
The answer is career clusters.
