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4 years ago

What is the equation of the line, in point-slope form, that passes through the points (-1, 7) and (-2, 3)?

Mathematics

1 answer:

myrzilka [38]4 years ago

4 0

Answer:

Step-by-step explanation:

(3-7)/(-2+1)= -4/-1= 4

y - 7 = 4(x + 1)

y - 7 = 4x + 4

y = 4x + 11

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Someone help me ( view picture below )

oksano4ka [1.4K]

Answer:

D. 13

Step-by-step explanation:

x = 5

2 x 5 + 3 = 13

5 + 8 = 13

meaning the side length has to be 13, also.

5 0

3 years ago

PLSSS HELP ME ASAPPPPPPP

Greeley [361]

THE ANSWER IS B $115 plz mark me brainliest i want points :’)

8 0

3 years ago

Read 2 more answers

I’d appreciate help ASAP please and thank you!

White raven [17]

<h3>Answer: Choice C) 40 </h3>

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Work Shown:

Plug in x = 0

$g(x) = 3^{2x}\\\\g(0) = 3^{2*0}\\\\g(0) = 3^{0}\\\\g(0) = 1\\\\$

This indicates that (0,1) is on the curve. This is the y intercept.

Do the same for x = 2

$g(x) = 3^{2x}\\\\g(2) = 3^{2*2}\\\\g(2) = 3^{4}\\\\g(2) = 81\\\\$

So we know that (2,81) is another point on this curve.

We need to find the slope of the line through (0,1) and (2,81) to get the slope of the secant line we want.

$m = \text{slope}\\\\m = \frac{\text{rise}}{\text{run}}\\\\m = \frac{\text{change in y}}{\text{change in x}}\\\\m = \frac{y_2-y_1}{x_2-x_1}\\\\m = \frac{g(2)-g(0)}{2-0}\\\\m = \frac{81-1}{2-0}\\\\m = \frac{80}{2}\\\\m = 40\\\\$

The slope of the line through (0,1) and (2,81) is m = 40. This value of m is exactly the slope of the secant line your teacher is asking for. This is why the answer is choice C.

5 0

3 years ago

a parabola has an x-intercept at 2, its axis of symmetry is the line x=4, and the y-coordinate of its vertex is 6. Determine the

nlexa [21]

Answer:

The standard equation of the parabola is:

$y=-\frac{3}{2}x^2+12x-18$

Step-by-step explanation:

An x intercept of 2 means that the point (2, 0) is in the graph of the parabola.

We can also write the general expression for the parabola in vertex form, since we can use the information on the coordinates of the vertex: (4, 6) - recall that the axis of symmetry of the parabola goes through the parabola's vertex, so the x-value of the vertex must be x=4.

$y-y_{vertex}=a\,(x-x_{vertex})^2\\y-6=a\,(x-4)^2$

Now we can find the value of the parameter "a" by using the extra information about the point (2, 0) at which the parabola intercepts the x-axis:

$y-6=a\,(x-4)^2\\0-6=a\,(2-4)^2\\-6=a\,4\\a=-\frac{6}{4} =-\frac{3}{2}$

Then the equation of the parabola becomes:

$y-6=-\frac{3}{2} \,(x-4)^2\\y-6=-\frac{3}{2} (x^2-8x+16)\\y-6=-\frac{3}{2}x^2+12x-24\\y=-\frac{3}{2}x^2+12x-18$

7 0

3 years ago

In a doctor's waiting room, there are 14 seats in a row. Eight people are waiting to be seated. Three of the 8 are in one family

lianna [129]

There are 14 chairs and 8 people to be seated. But among the 8. three will be seated together:

So 5 people and (3) could be considered as 6 entities:

Since the order matters, we have to use permutation:

¹⁴P₆ = (14!)/(14-6)! = 2,162,160, But the family composed of 3 people can permute among them in 3! ways or 6 ways. So the total number of permutation will be ¹⁴P₆ x 3!

2,162,160 x 6 = 12,972,960 ways.

Another way to solve this problem is as follow:

5 + (3) people are considered (for the time being) as 6 entities:

The 1st has a choice among 14 ways
The 2nd has a choice among 13 ways
The 3rd has a choice among 12 ways
The 4th has a choice among 11 ways
The 5th has a choice among 10 ways
The 6th has a choice among 9ways

So far there are 14x13x12x11x10x9 = 2,162,160 ways
But the 3 (that formed one group) could seat among themselves in 3!
or 6 ways:

Total number of permutation = 2,162,160 x 6 = 12,972,960

4 0

3 years ago