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Ray Of Light [21]
3 years ago
6

Marylou buys a package of 50 jewels to decorate 4 different pair of jeans.She uses the same number of jewels on each pair of jea

ns.How many jewels will she use for each pair of jeans?
Mathematics
1 answer:
Molodets [167]3 years ago
6 0

She can use 12 jewels for each pair of jeans. In fact, using 12 jewels per jeans implies that she will use 12 \cdot 4 = 48 jewels. The two remaining jewels can't be used on any pair of jeans, otherwise she wouldn't use the same number of jewels for each jeans.

This derives from the fact that, if you divide 50 by 4, you get a result of 12 with a remainder of 2.

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PYTHAGOREAN THEOREM
Sav [38]

Answer:

the answer is 29

Step-by-step explanation:

a^2 + b^2 = c^2 (btw ^ means to the power)

a and b are the legs. c is the hypotenuse

21^2 + 20^2 = c^2

441 + 400 = 481

then we have to square it.

the square root of 481= 29.

btw the hypotenuse is always going to be bigger than the legs.

hope it helps!! btw it is right!

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Please help me with these two math problems that I do not quite understand. This is urgent!
g100num [7]

Answer:

1)a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) a_{10}=4+8(10-1)\Rightarrow a_{10}=76

Step-by-step explanation:

1) To write an Arithmetic Sequence, as an Explicit Term, is to write a general formula to find any term for this sequence following this pattern:

a_{n}=a_{1}+d(n-1)\Rightarrow \left\{\begin{matrix}a_{n}=n^{th}\: term\\a_1=1st \: term \\d=\: difference\\n=n^{th}\, term\end{matrix}\right.

<em>"Write an explicit formula for each explicit formula A(n)=-1+(n-1)(-2)"</em>

This isn't quite clear. So, assuming you meant

Write an explicit formula for each term of this sequence A(n)=-1+(n-1)(-2)

As this A(n)=-1+(n-1)(-2)  is already an Explicit Formula, since it is given the first term a_{1}=-1 the common difference d=-2 let's find some terms of this Sequence through this Explicit Formula:

a_{n}=a_{1}+(n-1)d\Rightarrow a_{n}=-1-2(n-1)\\a_{2}=-1-2(2-1)\Rightarrow a_{2}=-3\\a_{3}=-1-2(3-1)\Rightarrow a_{3}=-5\\(...)\\a_{10}=-1-2(10-1)=-19

2) (4,12,20,28, ..) In this Arithmetic Sequence the common difference is 8, the first term value is 4.

Then, just plug in the first term and the common difference into the explicit formula:

a_{10}=4+8(10-1)\Rightarrow a_{10}=76

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